Các câu hỏi tương tự
\(\frac{2020}{2019}-\frac{2018}{2017}+\frac{2}{2017\cdot2019}3\cdot x-18\)
Tìm x biết
a) \(\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2019}\right).x=\frac{2018}{1}+\frac{2017}{2}+\frac{2016}{3}+...+\frac{2}{2017}+\frac{1}{2018}\)
b) \(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{2}{x\left(x+1\right)}=\frac{2017}{2019}\)
\(\frac{x+4}{2016}+\frac{x+3}{2017}=\frac{x+2}{2018}+\frac{x+1}{2019}\)
\(\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{2017}\right).x+2017=\frac{2018}{1}+\frac{2018}{2}+\frac{2020}{3}\). Tìm x
1. Cho A=\(1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{2017}-\frac{1}{2018}\)và B=\(\frac{1}{1010}+\frac{1}{1011}+...+\frac{1}{2017}+\frac{1}{2018}\)Tính \(\left(\frac{A}{B}\right)^{2018}\)
2. Tìm x biết
a)\(\frac{1}{1.3}+\frac{1}{3.5}+...+\frac{1}{x.\left(x+2\right)}=\frac{20}{41}\)
b)\(|x+2016|+|x+2017|+2018=3x\)
Rút gọn:
\(\frac{\frac{1}{2020}+\frac{2}{2019}+\frac{3}{2018}+...+\frac{2019}{2}+\frac{2020}{1}}{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2021}}\)
So sánh A và B:
\(A=\frac{2018^2}{2^{2018}+3^{2019}}+\frac{3^{2019}}{3^{2019}+5^{2020}}+\frac{5^{2020}}{5^{2020}+2^{2018}}\)
\(B=\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{2019.2020}\)
17 tháng 3 2019 lúc 22:58
Tìm x, biết:
a) \(x-\left\{\left[-x-\left(x+3\right)\right]-\left[\left(x+2018\right)-\left(x+2019\right)\right]+21\right\}=2020\)
b) \(\frac{1}{x}-\left\{\frac{1}{2.4}+\frac{1}{4.6}+\frac{1}{6.8}+...+\frac{1}{2018.2020}\right\}=\frac{1}{2019}\)
Help me! ( tặng 2 - 3 tk )
\(\frac{x+4}{2015}+\frac{x+3}{2016}=\frac{x+2}{2017}+\frac{x+1}{2018}\text{ }\text{ }\)