Tính giá trị của biểu thức:
\(\frac{\left(\frac{1}{6}+\frac{1}{10}+\frac{1}{15}\right):\left(\frac{1}{6}+\frac{1}{10}-\frac{1}{15}\right)}{\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{4}-\frac{1}{5}\right):\left(\frac{1}{4}-\frac{1}{6}\right)}\)
Tính nhanh:
A=\(\left(\frac{2}{5}+\frac{2}{9}+\frac{2}{11}\div\frac{7}{5}+\frac{7}{9}+\frac{7}{11}\right)\div\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{5}\div\frac{7}{6}-\frac{7}{8}+\frac{7}{10}\right)\)
\(A=\left(6:\frac{3}{5}-1\frac{1}{6}x\frac{6}{7}\right):\left(4\frac{1}{5}x\frac{10}{11}+5\frac{2}{11}\right)\)\(B=\left(1-\frac{1}{2}\right)x\left(1-\frac{1}{4}\right)x.......x\left(1-\frac{1}{2015}\right)x\left(1-\frac{1}{2016}\right)\)
\(C=5\frac{9}{10}:\frac{3}{2}-\left(2\frac{1}{3}x4\frac{1}{2}-2x2\frac{1}{3}\right):\frac{7}{4}\)
\(\left(\frac{1}{6}+\frac{1}{10}+\frac{1}{15}\right):\left(\frac{1}{6}+\frac{1}{10}-\frac{1}{15}\right)\)
M=\(\left(1-\frac{1}{3}\right)x\left(1-\frac{1}{6}\right)x\left(1-\frac{1}{10}\right)x\left(1-\frac{1}{15}\right)x\left(1-\frac{1}{21}\right)x\left(1-\frac{1}{28}\right)\)
Tính:
a,\(\frac{\left(3+\frac{1}{6}\right)-\frac{2}{5}}{\left(5-\frac{1}{6}\right)+\frac{7}{10}}\)
b,\(\frac{\left(4,08-\frac{2}{25}\right):\frac{4}{17}}{\left(6\frac{5}{9}-3\frac{1}{4}\right)x2\frac{2}{7}}\)
c,\(\frac{2-\frac{1}{4}+\frac{1}{3}-\frac{3}{5}}{3-\frac{1}{5}-\frac{5}{3}}\)
Bài1:Tính giá trị biểu thức sau:
A=\(\left(6:\frac{3}{5}-1\frac{1}{6}x\frac{6}{7}\right):\left(4\frac{1}{5}x\frac{10}{11}+5\frac{2}{11}\right)\)
Bài 2: Tính giá trị biểu thức:
B= \(\left(1-\frac{1}{2}\right)x\left(1-\frac{1}{3}\right)x\left(1-\frac{1}{4}\right)x\left(1-\frac{1}{5}\right)...\left(1-\frac{1}{2003}\right)x\left(1-\frac{1}{2004}\right)\)
ai xong sẽ có tích , phải làm giải từng bước ra nhé!
Tính : \(\frac{0,6:\frac{4}{5.}.1,25}{0,64-\frac{1}{25}}+\frac{\left(10-\frac{2}{25}\right):\frac{4}{70}}{\left(6\frac{5}{9}-3\frac{1}{4}\right).2\frac{1}{17}}+\frac{6}{5}.\frac{1}{2}:\frac{3}{5}\)
Tìm Y, biết \(\left(y-\frac{1}{2}\right)\div\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+.....+\frac{1}{90}\right)=\frac{1}{3}\)