\(\frac{\left(3^4.3^3\right)^3}{27^3}=\frac{\left(3^7\right)^3}{27^3}=\frac{3^{21}}{\left(3^3\right)^3}=\frac{3^{21}}{3^9}=3^{21-9}=3^{12}=531441\) không chia hết cho 2 vì chữ số tận cùng là 1
CHỨNG MINH :
\(\frac{\left(3^4.3^3\right)^3}{27^3}\) chia hết cho 2
Cho \(A=\left[\frac{n}{2}\right]+\left[n+\frac{1}{2}\right];B=\left[\frac{n}{3}\right]+\left[n+\frac{1}{3}\right]+\left[n+\frac{2}{3}\right]\)với giá trị nào của n thuộc Z thì :
a) A chia hết cho 2 ; b) B chia hết cho 3
a)A=\(\frac{16^3.3^{10}+120.6^9}{4^6.3^{12}+6^{11}}\) b)B=\(\frac{45}{19}-\left(\frac{1}{2}\left(\frac{1}{3}+\left(\frac{1}{4}\right)^{-1}\right)^-\right)^{-1}\) c)C=\(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^{10}.6^{19}-7.2^{29}.27^6}\)
d)D=\(\frac{2^{21}.3^5-4^6.81}{\left(2^2.3\right)^6+8^4.3^5}\) e) E=\(\left(6^9.2^{10}+12^{10}\right):\left(2^{19}.27^3+15.4^9.9^4\right)\)
f) F=\(\frac{3^6.45^4-15^{13}.5^{-9}}{27^4.24^3+45^6}\) g)G=\(\frac{\left(\frac{2}{5}\right)^7.5^7+\left(\frac{9}{4}\right)^3:\left(\frac{3}{16}\right)^3}{2^7.5^2+512}\) h)H=\(x+\frac{0,2-0,375+\frac{5}{11}}{-0,3+\frac{9}{16}-\frac{15}{22}}\)với x=-1/3
Bài 1 thực hiện phép tính
a)\(\frac{45}{19}-\left(\frac{1}{2}+\left(\frac{1}{3}+\left(\frac{1}{4}\right)^{-1}\right)^{-1}\right)^{-1}.\)
b) \(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^{10}.6^{19}-7.2^{29}.27^6}.\)
Bài 2. tìm x, biết:
a) 2(x-1) - 3(2x+2) - 4(2x+3) =16
b) \(3\frac{1}{2}:\left|2x-1\right|=\frac{21}{22}\)
c) |x2+|x-1|| = x2+2
Bài 3. Chứng minh rằng số có dạng abcabc luôn chia hết cho 11
Bài 4.tính:
a) A = \(\left(\frac{0,4-\frac{2}{9}+\frac{2}{11}}{1,4-\frac{7}{9}+\frac{7}{11}}-\frac{\frac{1}{3}-0,25+\frac{1}{5}}{1\frac{1}{6}-0,875+0,7}\right):\frac{2012}{2013}\)
b) B =\(4.\left(-\frac{1}{2}\right)^2-2.\left(-\frac{1}{2}\right)^2+3.\left(-\frac{1}{2}\right)+1\)
c) C =\(\frac{1}{2}:\left(-1\frac{1}{2}\right):1\frac{1}{3}:\left(-1\frac{1}{4}\right):1\frac{1}{5}:\left(-1\frac{1}{6}\right):...:\left(-1\frac{1}{100}\right)\)
d) D =\(\frac{4^6.9^5+6^9.120}{-8^4.3^{12}+6^{11}}\)
1)a/Chứng minh:\(A=\left(8.3^3\right).49.7^{13}\) chia hết cho 42
b/Chứng minh:\(32^8-8^{13}+4^9\)chia hết cho 72
c/Chứng minh:\(3^{21}-9^9\)chia hết cho 13
d/Chứng minh:\(\left(5^{2018}+5^{2017}+5^{2016}\right)\)chia hết cho 31
2)a/\(\frac{6^5.3^2}{4^3.9^3}\)
b/\(\frac{6^8.9^2}{4^3.81^3}\)
c/\(\frac{9^8.8^6}{16^4.3^{17}}\)
a) thực hiện phép tính :
\(A=\frac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}-\frac{5^{10}.7^3-25^5.49^2}{\left(125.7\right)^3+5^9.14^3}\)
b) chứng minh rằng : Với mọi số nguyên dương n thì :
\(3^{n+2}-2^{n+2}+3^n-2^n\)chia hết cho 10
Tìm x biết
\(|x+\frac{1}{3}|+\frac{4}{5}=|\left(-3,2\right)+\frac{2}{5}|+\left(27-\frac{3}{5}\right)\left(27-\frac{3^2}{6}\right)\left(27-\frac{3^3}{7}\right)...\left(27-\frac{3^{2010}}{2014}\right)\)
tìm x:
\(|x+\frac{1}{3}|+\frac{4}{5}=|\left(-3,2\right)+\frac{2}{5}|+\left(27-\frac{3}{5}\right)\left(27-\frac{3^2}{7}\right)\left(27-\frac{3^3}{7}\right)...\left(27-\frac{3^{2010}}{2014}\right)\)
\(\frac{20^5.5^{10}}{100^5}.\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
\(\left(\frac{4}{9}+\frac{1}{3}\right)^2+\left(\frac{3}{4}\right)^3:\left(\frac{3}{4}\right)^2:\left(\frac{-2}{3}\right)^3\)
