Question

\(\frac{\left(3^2.5.7^9\right).\left(3^5.5^3\right)}{\left(3^3.5^2.7^5\right).^2}\)

Answer 1

= \(\frac{3^2.5^4.7^9}{3^3.5^2.7^5.3^3.5^2.7^5}\)

=\(\frac{3^2.5^4.7^9}{3^6.5^4.7^{10}}\)

= \(\frac{1.1.1}{3^4.1.7}\)

= \(\frac{1}{567}\)

Answer 2

\(\frac{\left(3^2.5.7^9\right).\left(3^5.5^3\right)}{\left(3^3.5^2.7^5\right)^2}=\frac{\left(3^2.3^5\right).\left(5.5^3\right).7^9}{3^6.5^4.7^{10}}=\frac{3^7.5^4.7^9}{3^6.5^4.7^{10}}=\frac{3}{7}\)