\(\frac{7x-12}{5x-2}=\frac{9-7x}{-5x+1}\)
\(=>\frac{2x-10}{5x-2}+1=\frac{-7x+9}{-5x+1}=\frac{-2x+8}{-5x+1}+1\)
\(=>\frac{2x-10}{5x-2}=\frac{-2x+8}{-5x+1}=\frac{-\left(2x-8\right)}{-\left(5x-1\right)}=\frac{2x-8}{5x-1}\)
\(=>\frac{2x-10}{5x-2}=\frac{2x-8}{5x-1}\)
\(=>\frac{5x-1}{5x-2}=\frac{2x-8}{2x-10}\)
\(=>\frac{-1}{5x-2}=\frac{-2}{2x-10}\)
\(=>-2x+10=-10x+4\)
\(=>-2x+10x=4-10=-6\)
\(=>8x=-6\)
\(=>x=\frac{-6}{8}=\frac{-3}{4}\)
P/s ko chắc :v
Ta có: \(\frac{7x-12}{5x-2}=\frac{7x-9}{5x-1}\)
\(\Rightarrow\left(7x-12\right).\left(5x-1\right)=\left(7x-9\right).\left(5x-2\right)\)
\(\Leftrightarrow35x^2-7x-60x+12=35x^2-14x-45x+18\)
\(\Leftrightarrow\left(35x^2-35x^2\right)-\left(7x+60x-14x-45x\right)=18-12\)
\(\Leftrightarrow8x=6\)
\(\Leftrightarrow x=\frac{3}{4}\)
Vậy \(\Leftrightarrow x=\frac{3}{4}\)
\(\frac{7x-12}{5x-2}=\frac{9-7x}{-5x+1}\)
\(\left(7x-12\right)\left(-5x+1\right)=\left(9-7x\right)\left(5x-2\right)\)
\(-35x^2+7x+60x-12=45x-18-35x^2+14x\)
\(67x-12=59x-18\)
\(67x-12-59x=18\)
\(8x-12=-18\)
\(8x=-18+12\)
\(8x=-6\)
\(x=-\frac{6}{8}=-\frac{3}{4}\)
Ta có: \(\frac{7x-12}{5x-2}=\frac{7x-9}{5x-1}\)
\(\Rightarrow\left(7x-12\right).\left(5x-1\right)=\left(7x-9\right).\left(5x-2\right)\)
\(\Leftrightarrow35x^2-7x-60x+12=35x^2-14x-45x+18\)
\(\Leftrightarrow\left(35x^2-35x^2\right)-\left(7x+60x-14x-45x\right)=18-12\)
\(\Leftrightarrow-8x=6\)
\(\Leftrightarrow x=\frac{-6}{8}=-\frac{3}{4}\)
Vậy \(x=-\frac{3}{4}\)
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