e xin lỗi em ghi nhầm là lớp 7 chứ ko pk lớp 8 đâu ạ
e xin lỗi em ghi nhầm là lớp 7 chứ ko pk lớp 8 đâu ạ
Giải Phương trình
\(\left(2x-1\right)^3+\left(x+2\right)^3=\left(3x+1\right)^3\)
\(\frac{x-1988}{15}+\frac{x-1969}{17}+\frac{x-1946}{19}+\frac{x-1919}{21}=10\)
\(\frac{\left(2009-x\right)^2+\left(2009-x\right)\left(x-2010\right)+\left(x-2010\right)^2}{\left(2009-x^2\right)-\left(2009-x\right)\left(x-2010\right)+\left(x-2010\right)^2}=\frac{19}{49}\)
\(\frac{2x+9}{\left(x+1\right)\left(x+8\right)}-\frac{2x+15}{\left(x+8\right)\left(x+7\right)}+\frac{2x+10}{\left(x+7\right)\left(x+3\right)}=\frac{4}{3}\)
tính nhanh biểu thức sau:
A=\(\frac{1}{\left(x+1\right)\left(x+3\right)}+\frac{1}{\left(x+3\right)\left(x+5\right)}+\frac{1}{\left(x+5\right)\left(x+7\right)}+\frac{1}{\left(x+7\right)\left(x+9\right)}+\frac{1}{\left(x+9\right)\left(x+11\right)}\)
1. \(\frac{7}{8}x-5\left(x-9\right)=\frac{20x+1,5}{6}\)
2 . \(\frac{\left(2x+1\right)^2}{5}-\frac{\left(x+1\right)^2}{3}=\frac{7x^2-14x-5}{15}\)
3 . \(4\left(3x-2\right)-3\left(x-4\right)=7x+10\)
4. \(\frac{\left(x+10\right)\left(x+4\right)}{12}-\frac{\left(x+4\right)\left(2-x\right)}{4}=\frac{\left(x+10\right)\left(x-2\right)}{3}\)
Tính nhanh giá trị biểu thức sau :
A= \(\frac{1}{\left(x+1\right)\left(x+3\right)}+\frac{1}{\left(x+3\right)+\left(x+5\right)}+\frac{1}{\left(x+5\right)\left(x+7\right)}+\frac{1}{\left(x+7\right)\left(x+9\right)}+\frac{1}{\left(x+9\right)\left(x+11\right)}\)
Chứng minh: \(\frac{2}{x^2-1}+\frac{4}{x^2-4}+...+\frac{20}{x^2-100}=\frac{11}{\left(x-10\right)\left(x+1\right)}+\frac{11}{\left(x-9\right)\left(x+2\right)}+...+\frac{11}{\left(x-1\right)\left(x+10\right)}\)
Tính \(\frac{1}{x\left(x+1\right)\left(x+2\right)}\)+ \(\frac{1}{\left(x+1\right)\left(x+2\right)\left(x+3\right)}\)+..............+\(\frac{1}{\left(x+8\right)\left(x+9\right)\left(x+10\right)}\)
Tính(rút gọn)
a,\(\left(x-\frac{3}{x+2}\right)\left(x+\frac{2}{x+3}\right)\)
b,\(\left(x-\frac{28}{x-3}\right)\left(x-\frac{21}{x+4}\right)\)
Giải các phương trình:
a) \(\frac{1}{x-1}-\frac{3x^2}{x^3-1}=\frac{2x}{x^2+x+1}\)
b) \(\frac{3}{\left(x-1\right)\left(x-2\right)}+\frac{2}{\left(x-3\right)\left(x-1\right)}=\frac{1}{\left(x-2\right)\left(x-3\right)}\)
c) \(1+\frac{1}{x+2}=\frac{12}{8+x^3}\)
d) \(\frac{13}{\left(x-3\right)\left(2x+7\right)}+\frac{1}{2x+7}=\frac{6}{\left(x-3\right)\left(x+3\right)}\)