\(=\frac{5.2^{30}.3^{18}-3^{20}.2^2.2^{27}}{5.2^9.2^{19}.3^{19}-7.2^{29}\cdot3^{18}}=\frac{5.2^{30}.3^{18}-3^{20}.2^{29}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}=\frac{2^{29}.3^{18}\left(5.2-3^2\right)}{2^{28}.3^{18}\left(5.3-7.2\right)}=\frac{2\left(10-9\right)}{\left(15-14\right)}==\frac{2.1}{1}=2\)