Question

\(\frac{2x-1}{2}\)=\(\frac{4}{\left(2x-1\right)^2}\)

Answer 1

\(\frac{2x-1}{2}=\frac{4}{\left(2x-1\right)^2}\Leftrightarrow2x-1.\left(2x-1\right)^2=2.4\Leftrightarrow\left(2x-1\right)^3=8\)

\(\Rightarrow\left(2x-1\right)^3=2^3\Rightarrow2x-1=2\Rightarrow2x=2+1=3\Rightarrow x=\frac{3}{2}\)

Answer 2

x=\(\frac{3}{2}\)

Answer 3

x=3/2

tich ủng hộ nha

Answer 4

ko có x nguyên thỏa mãn

Answer 5

rut gon (2x-1)

ta duoc:1/2=4/(2x-1)

2x-1=8

x=9/2

Answer 6

=) (2x-1)(2x-1)^2=4*2

 (2x-1)^3=8

(2x-1)^3=2^3

=)2x-1=2

2x=3

x=3/2

duyet nha

Answer 7

Theo đầu bài ta có:
^{2x - 1}/₂ = ⁴/_{( 2x - 1 )²}
=> ( 2x - 1 )³ = 8
=> 2x - 1 = 2
=> 2x = 3
=> x = ³/₂