Question

\(\frac{2^5\cdot7+2^5}{2^5\cdot2^5-2^5\cdot3}\)và \(\frac{3^4\cdot5\cdot< -3>^6}{3^4\cdot13\cdot3^4}\)

Quy Đồng gium mk nha.truoc 2 h voi help help

Answer 1

ta có: \(\frac{2^5.7+2^5}{2^5.2^5-2^5.3}=\frac{2^5.\left(7+1\right)}{2^5.\left(2^5-3\right)}=\frac{8}{2^5-3}=\frac{8}{29}=\frac{104}{377}\)

\(\frac{3^4.5.\left(-3\right)^6}{3^4.13.3^4}=\frac{3^{10}.5}{3^8.13}=\frac{3^2.5}{13}=\frac{45}{13}=\frac{1305}{377}\)

\(\Rightarrow\frac{104}{377}< \frac{1305}{377}\Rightarrow\frac{2^5.7+2^5}{2^5.2^5-2^5.3}< \frac{3^4.5.\left(-3\right)^6}{3^4.13.3^4}\)

Answer 2

Ta cứ tính ra tử số và mỗi số của từng phân số ra nhé Jerry Gaming:

\(\frac{2^5.7+2^5}{2^5.2^5-2^5.3}\)= \(\frac{2^5.\left(7+1\right)}{2^5.\left(2^5-3\right)}=\frac{2^5.8}{2^5.\left(32-3\right)}=\frac{32.8}{2^5.29}=\frac{32.8}{32.29}=\frac{8}{29}\)

\(\frac{3^4.5.\left(-3\right)^6}{3^4.13.3^4}\)= \(\frac{3^4.5.3^6}{3^8.13}=\frac{3^{10}.5}{3^8.13}=\frac{3^2.5}{13}=\frac{9.5}{13}=\frac{45}{13}\)

\(\frac{8}{29}\)và \(\frac{45}{13}\)MSC: 377

Ta có:

\(\frac{8}{29}=\frac{8.13}{29.13}=\frac{104}{377}\)

\(\frac{45}{13}=\frac{45.29}{13.29}=\frac{1305}{377}\)

Vậy quy đồng \(\frac{2^5.7+2^5}{2^5.2^5-2^5.3}\)và \(\frac{3^4.5.\left(-3\right)^6}{3^4.13.3^4}\)ta được \(\frac{104}{377}\)và \(\frac{1305}{377}\)

Chúc bạn học tốt!