Question

\(\frac{2^{10}.3^{31}+2^{40}.3^6}{2^{11}.3^{31}+2^{41}.3^6}\)

Tính

Answer 1

\(\frac{2^{10}.3^{31}+2^{40}.3^6}{2^{11}.3^{31}+2^{41}.3^6}=\frac{2}{2+2}=\frac{2}{4}=\frac{1}{2}\)

Answer 2

2^10 .3^6 .3^25 + 2^10 .2^30 .3^6

2 ^11 .3^6 . 3^25 + 2^ 11 . 2^ 30 .3 ^6

2^ 10 . 3^ 6 .(2^ 30 + 3^ 25 )

2^11.3 ^ 6. ( 3^ 25 +2^ 30 )

2 ^ 10. 3^ 6

2^ 11 . 3^6

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