(A\(\cup\)B)\C 

GIẢ SỬ x\(\in\)C THÌ x\(\notin\)(A\(\cup\)B); x\(\notin\)(A\(\cup\)B) THÌ \(\left[{}\begin{matrix}\left\{{}\begin{matrix}x\in A\\x\notin B\end{matrix}\right.\\\left\{{}\begin{matrix}x\notin A\\x\in B\end{matrix}\right.\end{matrix}\right.\)

(A\(\cap\)B)\(\cup\)A=A

(A\(\cap\)B)\(\cup\)A = (A\(\cup\)A)\(\)\(\cap\) (A\(\cup\)B) = A \(\cap\)(A\(\cup\)B) = A

\(A\backslash\left(B\cap C\right)=A\B\)\(\cup A\C\)

\(\left[{}\begin{matrix}x\in A\\\left\{{}\begin{matrix}x\in B\\x\in C\end{matrix}\right.\end{matrix}\right.\)

\(\left[{}\begin{matrix}\left\{{}\begin{matrix}x\in A\\x\notin B\end{matrix}\right.\\\left\{{}\begin{matrix}x\in A\\x\notin C\end{matrix}\right.\end{matrix}\right.\)