\(\frac{1}{5}+\frac{1}{15}=\frac{3}{15}+\frac{1}{15}=\frac{4}{15}\)
1/5 ta quy đồng bằng 3/15
3/15 + 1/ 15 = 8/15
\(\frac{1}{5}\)+\(\frac{1}{15}\)= \(\frac{15}{75}\)+\(\frac{5}{75}\)= \(\frac{20}{75}\)
\(\frac{1}{5}+\frac{1}{15}=\frac{3}{15}+\frac{1}{15}=\frac{4}{15}\)
1/5 ta quy đồng bằng 3/15
3/15 + 1/ 15 = 8/15
\(\frac{1}{5}\)+\(\frac{1}{15}\)= \(\frac{15}{75}\)+\(\frac{5}{75}\)= \(\frac{20}{75}\)
\(\frac{\left(\frac{1}{6}+\frac{1}{10}+\frac{1}{15}\right)\div\left(\frac{1}{6}+\frac{1}{10}-\frac{1}{15}\right)}{\left(\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+\frac{1}{5}\right)\div\left(\frac{1}{4}-\frac{1}{6}\right)}\)
Tính giá trị của biểu thức:
\(\frac{\left(\frac{1}{6}+\frac{1}{10}+\frac{1}{15}\right):\left(\frac{1}{6}+\frac{1}{10}-\frac{1}{15}\right)}{\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{4}-\frac{1}{5}\right):\left(\frac{1}{4}-\frac{1}{6}\right)}\)
1) \(79\frac{19}{35}.\frac{7}{90}+15\frac{16}{35}.\frac{7}{90}\)
2)\(\left(3\frac{1}{5}-\frac{1}{11}\right).11\)
3)\(4\frac{1}{5}:\left(2\frac{1}{3}.1\frac{2}{5}\right)\)
4)\(13,2.\frac{15}{64}-\left(\frac{4}{5}+\frac{2}{3}\right):3\frac{2}{3}\)
\(\frac{x}{2008}-\frac{1}{10}-\frac{1}{15}-\frac{1}{21}-...-\frac{1}{120}=\frac{5}{8}\)
Tính nhanh
a)\(\frac{11}{15}+\frac{5}{7}+\frac{2}{7}+\frac{4}{15}\)
b)\(\frac{5}{9}x\frac{1}{2}x\frac{5}{9}x\frac{6}{4}\)
c)\(\frac{7}{8}:\frac{1}{2}+\frac{9}{8}:\frac{1}{2}\)
d)\(\frac{17}{10}+\frac{1}{2}-\frac{7}{10}\)
tính nhanh
\(a,\frac{11}{15}+\frac{5}{7}+\frac{2}{7}+\frac{4}{15}\)
\(b,\frac{5}{9}x\frac{1}{2}+\frac{5}{9}x\frac{6}{4}\)
\(c,\frac{7}{8}:\frac{1}{2}+\frac{9}{8}:\frac{1}{2}\)
\(d,\frac{17}{10}+\frac{1}{2}-\frac{7}{10}\)
Tính nhanh
a)\(\frac{11}{15}+\frac{5}{7}+\frac{2}{7}+\frac{4}{15}\)
b)\(\frac{5}{9}x\frac{1}{2}+\frac{5}{9}x\frac{6}{4}\)
c)\(\frac{7}{8}:\frac{1}{2}+\frac{9}{8}:\frac{1}{2}\)
d)\(\frac{17}{10}+\frac{1}{2}-\frac{7}{10}\)
\(\frac{1}{1\cdot5}+\frac{1}{5\cdot10}+\frac{1}{10\cdot15}+\frac{1}{15\cdot20}+...........+\frac{1}{2005\cdot2010}\)
\(\frac{\left(\frac{3}{15}+\frac{1}{4}+\frac{7}{20}\right)\times\frac{17}{49}}{5\frac{1}{3}+\frac{2}{5}}\)
So sánh \(A\)với\(13\),biết rằng:
\(A=\frac{13}{15}+\frac{7}{5}+\frac{3}{4}+\frac{1}{5}+\frac{1}{7}+\frac{19}{20}+\frac{5}{4}+\frac{1}{3}+\frac{1}{6}+\frac{1}{13}+\frac{17}{23}+\frac{9}{8}+\frac{2}{5}+\frac{1}{7}+\frac{1}{25}+\frac{3}{2}+\frac{1}{8}+\frac{1}{19}+\frac{1}{9}+\frac{1}{97}\)