Đặt A=1/51+1/52+1/53+...+1/52008
5A=1+1/51+1/52+...+1/52007
5A-A=(1+1/51+1/52+...+1/52007)-(1/51+1/52+1/53+...+1/52008)
4A=1-1/52008<1
A<1/4
Đặt A=1/51+1/52+1/53+...+1/52008
5A=1+1/51+1/52+...+1/52007
5A-A=(1+1/51+1/52+...+1/52007)-(1/51+1/52+1/53+...+1/52008)
4A=1-1/52008<1
A<1/4
chứng minh
\(\frac{1}{5}+\frac{1}{5^2}+\frac{1}{5^3}+......+\frac{1}{5^{2008}}<\frac{1}{4}\)
Giúp mình bài này với
Tính
\(A=\frac{2008+\frac{2007}{2}+\frac{2006}{3}+\frac{2005}{4}+.....+\frac{2}{2007}+\frac{1}{2008}}{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+.....+\frac{1}{2008}+\frac{1}{2009}}\)
Cho A=\(\frac{1}{5^2}+\frac{2}{5^3}+\frac{3}{5^4}+...+\frac{n}{5^{n+1}}+...+\frac{11}{5^{12}}\)với n\(\inℕ\).Chứng minh rằng A<\(\frac{1}{16}\)
Giúp mình với, hiện đang cần gấp lắm.
\(S=\frac{2008+\frac{2007}{2}+\frac{2006}{3}+\frac{2005}{4}+...+\frac{2}{2007}+\frac{1}{2008}}{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+...+\frac{1}{2008}+\frac{1}{2009}}\)
S=?
\(\frac{-5}{3}-\left(\frac{4}{5}-\frac{1}{2}\right)-\left|\frac{3}{4}-\frac{5}{2}+\frac{1}{3}\right|\)
NHANH HỘ MÌNH NHA, MÌNH CÁM ƠN NHÌU !!!
Giá trị của biểu thức \(A=\frac{2008+\frac{2007}{2}+\frac{2006}{3}+\frac{2005}{4}+...+\frac{2}{2007}+\frac{1}{2008}}{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+...+\frac{1}{2008}+\frac{1}{2009}}\)là \(A=.............\)
chứng minh\(\frac{1}{2}-\frac{1}{3}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{2012}-\frac{1}{2013}+\frac{1}{2014}< \frac{2}{5}\)
1) \(\frac{2}{5}x\frac{1}{3}-\frac{2}{15}:\frac{1}{5}+\frac{3}{5}x\frac{1}{3}\)
2)\(\left(3\frac{1}{3}+2,5\right):\left(3\frac{1}{6}-4\frac{1}{5}\right)-\frac{11}{31}\)
3)\(\left[6+\left(\frac{1}{2}\right)^3-\left|-\frac{1}{2}\right|\right]:\frac{3}{12}\)
4)\(\frac{18}{37}+\frac{8}{24}+\frac{19}{37}-1\frac{23}{24}+\frac{2}{3}\)
5)\(\left(-2\right)^3x\left(\frac{3}{4}-0,25\right):\left(2\frac{1}{4}-1\frac{1}{6}\right)\)
6)\(\left(\frac{2}{5}\right)^2+5\frac{1}{2}x\left(45-2\right)+\frac{23}{4}\)
7)\(\frac{4}{9}-19\frac{1}{3}-\frac{4}{9}x39\frac{1}{3}\)
8)\(\left(-\frac{1}{2}\right)^2:\frac{1}{4}-2x\left(-\frac{1}{2}\right)^2\)
9)\(125\%x\left(-\frac{1}{2}\right)^3:\left(1\frac{5}{16}-1,5\right)+2008^0\)
giúp mình nha mai mình học rùi
tính :
\(\frac{1,6:\left(1\frac{3}{5}.1,25\right)}{0,64-\frac{1}{25}}+\frac{\left(1,08-\frac{2}{25}\right):\frac{4}{7}}{\left(5\frac{5}{9}-2\frac{1}{4}\right).2\frac{2}{17}}+0,6.0,5:\frac{2}{5}\)( các banmj giải hộ mình nha . giải đúng , chi tiết mình tick)