\(\frac{1}{4}+\frac{1}{3}:3x=-5\)
\(\frac{1}{3}:3x=-5-\frac{1}{4}\)
\(\frac{1}{3}:3x=-\frac{21}{4}\)
\(3x=\frac{1}{3}:\left(-\frac{21}{4}\right)\)
\(3x=-\frac{4}{63}\)
\(x=-\frac{4}{63}:3\)
\(x=-\frac{4}{189}\)
a. 2.(\(\frac{1}{4}\)- 3x ) = \(\frac{1}{5}\)- 4x
b. \(\frac{2}{5}\)- 3 ( \(\frac{1}{3}\)- x ) = \(\frac{1}{4}\)- 7x
c. 5 | x - 3 | = \(\frac{5}{7}\)
d. -3 | 2x - 5 | = \(\frac{-3}{4}\)
e. \(\frac{1}{4}\). | 3x - 7 | = \(\frac{1}{5}\)
g. -\(\frac{7}{3}\). | -3x - \(\frac{1}{2}\)| = \(\frac{-7}{6}\)
\(\left(3x-1\right).\left(\frac{-1}{2}x+5\right)=0\)
\(\frac{1}{4}+\frac{1}{3}:\left(2x-1\right)=-5\)
\(\left(2x+\frac{3}{5}\right)^{^2}-\frac{9}{25}=0\)
\(3\left(3x-\frac{1}{2}\right)+\frac{1}{9}=0\)
bài 1 tim x y thuộc z
\(\frac{3}{x-5}=\frac{x-5}{27}\)
\(\frac{3}{x}=\frac{y}{35}=\frac{-36}{84}\)
\(\frac{3x+1}{-2}=\frac{-8}{3x+1}\)
\(\frac{3}{x-5}=\frac{-4}{x+2}\)
tìm x trong các tỉ lệ thức sau :
\(a. \frac{x+5}{x+9}=\frac{x+4}{x+3}\)
\(b. \frac{2x-7}{2x+11}=\frac{5-3x}{4-2x}\)
\(c. \frac{3x+5}{-3x+11}=\frac{7x-5}{7-7x}\)
\(d. \frac{5x-3}{x+1}=\frac{5x-7}{x-1}\)
\(\frac{3.\left(2x-1\right)}{4}-\frac{3x+1}{10}+1=\frac{2.\left(3x+2\right)}{5}\)
giúp với!!!
Tìm x
a/\(\frac{1}{24.25}+\frac{1}{25.26}+...+\frac{1}{29.30}+x\div\frac{1}{3}=-4\)
b/\(\frac{1}{10}+\frac{1}{40}+\frac{1}{88}+...+\frac{1}{\left(3x+2\right)\left(3x+5\right)}=\frac{3}{20}\)
\(\frac{1}{4}+\frac{1}{3}:3x=-5\)
\(\frac{1}{4}+\frac{1}{3}:3x+-5\)
Tìm x,y biết :
\(a,\)\(-\frac{1}{2}\)\(\left(3-2x\right)\)\(-7=5-\frac{1}{3}\left(x-\frac{4}{5}\right)\)
\(b,\left(5-\frac{3x}{2}\right):-1\frac{3}{8}=-7\frac{1}{3}\)
\(c,\left(2+3x\right)^2+\left|3x+2y\right|=0\)
Tìm x, biết :
a, \(60\%x+0,4x+x:3=2\)
b, \(\left|2x-5\right|-7=\left(\frac{1}{49}-\frac{1}{3^2}\right)\left(\frac{1}{49}-\frac{1}{4^2}\right)...\left(\frac{1}{49}-\frac{1}{2015^2}\right)\)
c, \(\frac{x+1}{1}+\frac{2x+3}{3}+\frac{3x+5}{5}+...+\frac{20x+39}{39}=22+\frac{4}{3}+\frac{6}{5}+...+\frac{40}{39}\)
