\(\frac{12}{1-9x^2}\)=\(\frac{1-3x}{1+3x}\)-\(\frac{1+3x}{1-3x}\)
\(\frac{2x-8}{6}-\frac{3x-1}{4}=\frac{9x-2}{8}+\frac{3x-1}{12}\)
Phương trình chứa ẩn ở mẫu
Giai các phương trình sau
1. \(\frac{7x-3}{x-1}=\frac{2}{3}\)
2. \(\frac{5x-1}{3x+2}=\frac{5x-7}{3x-1}\)
3. \(\frac{1-x}{x+1}+3=\frac{2x+3}{x+1}\)
4. \(\frac{1-6x}{x-2}+\frac{9x+4}{x+2}=\frac{x\left(3x-2\right)+1}{x^2-4}\)
5. \(\frac{3x+2}{3x-2}-\frac{6}{2+3x}=\frac{9x^2}{9x^2-4}\)
6. \(1+\frac{1}{x+2}=\frac{12}{8-x^3}\)
Giải phương trình sau :
\(\frac{2x-8}{6}-\frac{3x+1}{4}=\frac{9x-2}{8}+\frac{3x-1}{12}\)
a) (\((\frac{3x}{1-3x}+\frac{2x}{3x+1}):\frac{6x^2+10x}{1-6x+9x^2}\)
GIẢI PHƯƠNG TRÌNH
a)\(\frac{1-x}{x+1}+3=\frac{2x+3}{x+1}\)
b)\(\frac{1}{x+1}-\frac{5}{x-2}=\frac{15}{\left(x+1\right)\left(2-x\right)}\)
c)\(\frac{12}{1-9x^2}=\frac{1-3x}{1+3x}-\frac{1+3x}{1-3x}\)
d)\(\frac{x+4}{x^2-3x+2}+\frac{x+1}{x^2-4x+3}=\frac{2x+5}{x^2-4x+3}\)
Rút gọn
a) \(\left(\frac{4}{x^3-9x}+\frac{1}{x+3}\right):\left(\frac{x-3}{x^2+3x}-\frac{x}{3x+9}\right)\)
b) \(\left(\frac{2}{x-2}-\frac{2}{x+2}\right).\frac{x^2+4x+4}{8}\)
c) \(\left(\frac{3x}{1-3x}+\frac{2x}{3x+1}\right):\frac{6x^2+10x}{1-6x+9x^2}\)
a)\(\frac{1}{3x-2}-\frac{4}{3x+2}-\frac{3x-6}{4-9x^2}\)
b) \(\frac{1}{x-1}-\frac{x^3-x}{x^2+1}\left(\frac{1}{x^2-2x+1}+\frac{1}{1-x^2}\right)\)
giải phương trình sau:
a) \(\frac{3x+2}{3x-2}-\frac{6}{2+3x}=\frac{9x^2}{9x-4}\\\)
b) \(\frac{3}{5x-1}+\frac{2}{3-5x}=\frac{4}{\left(1-5x\right)\left(x-3\right)}\)
c)\(\frac{3}{1-4x}=\frac{2}{4x+1}-\frac{8+6x}{16x^2-1}\)
d) \(5+\frac{76}{x^2-16}=\frac{2x-1}{x+4}-\frac{3x-1}{4-x}\)