Trần Thùy Dung nó đã bảo \(990\ne99\cdot100\) rùi mà vẫn tách như v
=\(\frac{1}{4.5}+\frac{1}{5.6}+...+\frac{1}{99.100}\)
=\(\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{99}-\frac{1}{100}\)
=\(\frac{1}{4}-\frac{1}{100}\)
=\(\frac{24}{100}=\frac{6}{25}\)
\(\frac{1}{4x5}+\frac{1}{5x6}+\frac{1}{6x7}\) \(+\frac{1}{7x8}+...+\frac{1}{99x100}\)
\(\frac{1}{4}-\frac{1}{5}+\frac{1}{5}+\frac{1}{6}\) \(+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}\) \(+...+\frac{1}{99}-\frac{1}{100}\)
\(\frac{1}{4}-\frac{1}{100}=\frac{6}{25}\)
ko sai đề đâu nha mấy bạn
cố lên
Ban sua 990 thanh 992
=\(\frac{1}{4\cdot5}+\frac{1}{5\cdot6}+\frac{1}{6\cdot7}+...+\frac{1}{31\cdot32}\)
=\(\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{31}-\frac{1}{32}\)
=\(\frac{1}{4}-\frac{1}{32}\)
=\(\frac{7}{32}\)