Ta có: \(D\left(-1\right)=2\cdot D\left(1\right)\)
\(\Leftrightarrow-\left(-1\right)^2+a\cdot\left(-1\right)=2\cdot\left(-1^2\right)+a\)
\(\Leftrightarrow-1-a=-2+a\)
\(\Leftrightarrow-a-1+2-a=0\)
\(\Leftrightarrow-2a+1=0\)
\(\Leftrightarrow-2a=-1\)
hay \(a=\dfrac{1}{2}\)