Chất sản phẩm: \(m_{tt}=\dfrac{m_{lt}.H\%}{100\%}\)
Chất tham gia: \(m_{tt}=\dfrac{m_{lt}.100\%}{H\%}\)
\(n_{Fe}=2n_{Fe_2O_3}=2.\dfrac{3,6}{160}=0,045\left(mol\right)\Rightarrow m_{Fe.tạo}=0,045.56=2,52\left(g\right)\\ \Rightarrow m_{Fe.thực.tế}=\dfrac{2,52.80\%}{100\%}=2,016\left(g\right)\)