Tóm tắt: \(x\left(g\right)CH_4\) a) Viết PTHH.
64g O2 b) Tìm x,y biết y:x=2,25
44g CO2
\(y\left(g\right)H_2O\)
\(n_{O_2}=\dfrac{64}{32}=2\left(mol\right)\); \(n_{CO_2}=\dfrac{44}{44}=1mol\)
\(CH_4+2O_2\rightarrow2H_2O+CO_2\uparrow\)
1 2 2 1
\(x=m_{CH_4}=1\cdot16=16\left(g\right)\)
\(\dfrac{y}{x}=2,25\Leftrightarrow y=m_{H_2O}=2,25\cdot16=36\left(g\right)\)