a, \(n_{H_2O}=\dfrac{3,6}{18}=0,2\left(mol\right)\)
PT: \(CH_4+2O_2\underrightarrow{t^o}CO_2+2H_2O\)
______0,1____0,2___0,1_____0,2 (mol)
m = 0,1.16 = 1,6 (g)
V = 0,1.24,79 = 2,479 (l)
b, VO2 (đkc) = 0,2.24,79 = 4,958 (l)
VO2 (đktc) = 0,2.22,4 = 4,48 (l)