\(n_{CO_2}=\dfrac{6,6}{44}=0,15\left(mol\right)\\ n_{H_2O}=\dfrac{3,15}{18}=0,175\left(mol\right)\\ n_{N_2}=\dfrac{0,61975}{2479}=0,025\left(mol\right)\)
=> \(\left\{{}\begin{matrix}n_{C\left(X\right)}=n_{CO_2}=0,15\left(mol\right)\left(BT.C\right)\\n_{H\left(X\right)}=2n_{H_2O}=2.0,175=0,35\left(mol\right)\left(BT.H\right)\\n_{N\left(X\right)}=2n_{N_2}=0,025.2=0,05\left(mol\right)\left(BT.N\right)\end{matrix}\right.\)
Gọi CTHH của X là \(C_xH_yN_z\)
Có: \(x:y:z=0,15:0,35:0,05=3:7:1\)
=> CTĐG: \(C_3H_7N=57\left(\dfrac{g}{mol}\right)\)
=> X có chứa Oxi => CTPT: \(C_3H_7O_aN\)
\(M_X=44,5.2=89\) g/mol
=> \(a=\dfrac{89-57}{16}=2\)
=> CTPT của X: \(C_3H_7O_2N\)
