Ta có: \(\left\{{}\begin{matrix}n_{Al}=\dfrac{m}{M}=\dfrac{2,7}{27}=0,1\left(mol\right)\\n_{O_2}=\dfrac{V_{\left(đktc\right)}}{22,4}=\dfrac{33,6}{22,4}=1,5\left(mol\right)\end{matrix}\right.\)
PTHH: \(2Mg+O_2\xrightarrow[]{t^o}2MgO\)
\(4Al+3O_2\xrightarrow[]{t^o}2Al_2O_3\)
Theo PTHH: \(n_{O_2}=\dfrac{1}{2}.n_{Mg}+\dfrac{3}{4}.n_{Al}\)
=> \(n_{Mg}=2.\left(1,5-\dfrac{3}{4}.0,1\right)=2,85\left(mol\right)\)
=> \(\left\{{}\begin{matrix}m_{Mg}=n.M=2,85.24=68,4\left(g\right)\\m_{O_2}=n.M=1,5.32=48\left(g\right)\end{matrix}\right.\)
ĐLBTKL: \(m_{MgO}+m_{Al_2O_3}=m_{Al}+m_{Mg}+m_{O_2}\)
=> \(m_{sản.phẩm}=m_{MgO}+m_{Al_2O_3}=2,7+68,4+48=119,4\left(g\right)\)
