Ta có: \(n_{C_2H_2}+n_{C_2H_4}+n_{C_2H_6}=n_{hh}=\dfrac{3,36}{22,4}=0,15\left(mol\right)\)
BTNT C, có: \(n_{CaCO_3}=n_{CO_2}=2n_{C_2H_2}+2n_{C_2H_4}+2n_{C_2H_6}=0,15.2=0,3\left(mol\right)\)
\(\Rightarrow m_{CaCO_3}=0,3.100=30\left(g\right)\)
Bạn tham khảo nhé!