a) \(n_{CO2}=\dfrac{6,72}{22,4}=0,3\left(mol\right);n_{H2O}=\dfrac{5,4}{18}=0,3\left(mol\right)\)
Ta thấy : \(n_{H2O}=n_{CO2}\rightarrow Anken\left(C_nH_{2n}\right)\)
\(\rightarrow n=\dfrac{n_{CO2}}{n_{anken}}=\dfrac{0,3}{0,1}=3\)
\(\rightarrow CTPT:C_3H_6\)
b) \(CTCT:CH_2=CH-CH_3\)