a)\(PTHH:2H_2+O_2\underrightarrow{t^o}2H_2O\)
b)\(n_{H_2}=\dfrac{3,6}{22,4}=0,16\left(m\right)\)
\(PTHH:2H_2+O_2\underrightarrow{t^o}2H_2O\)
tỉ lệ :2 1 2
số mol :0,16 0,08 0,16
\(V_{O_2}=0,08.22,4=1,792\left(l\right)\)
\(m_{O_2}=0,08.32=2,56\left(g\right)\)
\(m_{H_2O}=0,16.18=2,88\left(g\right)\)