\(n_{CO_2}=\dfrac{8.8}{44}=0.2\left(mol\right)\)
\(n_{H_2O}=\dfrac{5.4}{18}=0.3\left(mol\right)\)
\(m_O=3-0.2\cdot12-0.3\cdot2=0\)
\(n_A=\dfrac{3}{30}=0.1\left(mol\right)\)
\(\text{Số nguyên tử C : }\dfrac{0.2}{0.1}=2\)
\(\text{Số nguyên tử H : }\dfrac{0.3\cdot2}{0.1}=6\)
\(CT:C_2H_6\)