Gọi \(\left\{{}\begin{matrix}n_{CuO}=a\left(mol\right)\\n_{ZnO}=b\left(mol\right)\end{matrix}\right.\)
`=> 80a + 81b = 24,1 (1)`
\(n_{CO}=\dfrac{6,72}{22,4}=0,3\left(mol\right)\)
PTHH:
\(CuO+CO\xrightarrow[]{t^o}Cu+CO_2\\ ZnO+CO\xrightarrow[]{t^o}Zn+CO_2\)
Theo PT: \(n_{CO_2}=n_{CO}=n_{CuO}+n_{ZnO}=a+b=0,3\left(2\right)\)
Từ `(1), (2) => a = 0,2; b = 0,1`
\(\Rightarrow\left\{{}\begin{matrix}\%m_{CuO}=\dfrac{0,2.80}{24,1}.100\%=66,4\%\\\%m_{ZnO}=100\%-66,4\%=33,6\%\end{matrix}\right.\)
\(V_{CO_2}=0,3.22,4=6,72\left(l\right)\)
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