Question

Đơn giản các biểu thức

a) -b-(b-a+c)             b) -(a-b+c)-(c-a)

c) b-(b+a-c)               d) a-(-b+a-c)

Answer 1

\(\text{a) -b-(b-a+c) }\)

\(=-b-b+a-c\)

\(=-2b+a-c\)

\(\text{ b) -(a-b+c)-(c-a)}\)

\(=-a-b-c-c+a\)

\(=\left(-a+a\right)+\left(-b\right)+\left(-c-c\right)\)

\(=-b+\left(-2c\right)\)

\(\text{c) b-(b+a-c)}\)

\(=b-b-a+c\)

\(=-a+c\)

\(\text{ d) a-(-b+a-c)}\)

\(=a+b-a+c\)

\(=\left(a-a\right)+b+c\)

\(=b+c\)

học tốt

Answer 2

a) -b-(b-a+c)

= −b − b + a − c

= −2b + a − c

b) -(a-b+c)-(c-a)

= −a − b − c − c + a

= −a + a + −b + −c − c

= −b + −2c

c) b-(b+a-c)

= b − b − a + c

= −a + c

d) a-(-b+a-c)

= a + b − a + c

= a − a + b + c

= b + c