a)\(R_1ntR_2ntR_3\Rightarrow R_{tđ}=R_1+R_2+R_3=3+8+7=18\Omega\)
\(I=\dfrac{U}{R}=\dfrac{36}{18}=2A\)
b)\(I'=\dfrac{I}{2}=1A\Leftrightarrow R_{tđ}=\dfrac{U}{I'}=36\Omega\)
\(R_{12}=3+8=11\Omega\)\(< R_{tđ}\Rightarrow\) Mắc \(R_3\) nối tiếp với mạch.
\(R'=R_3=R-R_{12}=36-11=25\Omega\)