\(a,=\dfrac{x}{x-3}:\left(\dfrac{x}{x\left(x-3\right)}-\dfrac{2}{x}\right)\)
\(=\dfrac{x}{x-3}:\left(\dfrac{x-2\left(x-3\right)}{x\left(x-3\right)}\right)\)
\(=\dfrac{x}{x-3}.\dfrac{x\left(x-3\right)}{x-2x+6}\)
\(=\dfrac{x}{x-3}.\dfrac{x\left(x-3\right)}{-x+6}\)
\(=\dfrac{x^2}{-x+6}\)
Vậy \(M=\dfrac{x^2}{-x+6}\)