=>2x=6(x-11)
=>6x-66=2x
=>4x=66
=>x=33/2
\(\dfrac{x}{6}=\dfrac{x-11}{2}\\ \Rightarrow\dfrac{x}{6}=\dfrac{3\left(x-11\right)}{6}\\ \Rightarrow x=3x-33\\ \Rightarrow x-3x+33=0\\ \Rightarrow-2x=-33\\ \Rightarrow x=-\dfrac{33}{-2}=\dfrac{33}{2}=16,5\)
=>2x=6(x-11)
=>6x-66=2x
=>4x=66
=>x=33/2
\(\dfrac{x}{6}=\dfrac{x-11}{2}\\ \Rightarrow\dfrac{x}{6}=\dfrac{3\left(x-11\right)}{6}\\ \Rightarrow x=3x-33\\ \Rightarrow x-3x+33=0\\ \Rightarrow-2x=-33\\ \Rightarrow x=-\dfrac{33}{-2}=\dfrac{33}{2}=16,5\)
ok giúp t thêm vài câu nữa đi :')
Tính hợp lý \(\dfrac{2}{11}\)-\(\dfrac{3}{8}\)+\(\dfrac{4}{11}\)-\(\dfrac{6}{11}\)-\(\dfrac{5}{8}\)
Số x thoả mãn \(\dfrac{1}{4}\)+\(\dfrac{x}{12}\)=\(\dfrac{8}{12}\)
Tìm x biết \(\dfrac{1}{2}\)-(x-\(\dfrac{5}{11}\))=\(\dfrac{-3}{4}\)
An đọc 1 quyển sách trong 3 ngày. Ngày thứ nhất An đọc đc \(\dfrac{1}{11}\) quyển sách,ngày thứ hai An đọc đc \(\dfrac{8}{11}\) quyển sách.Hỏi trong 2 ngày An đọc đc bao nhiêu phần quyển sách?
Tìm x;y ϵ Z sao cho :
\(\dfrac{x}{2}=\dfrac{2}{y}+\dfrac{11}{6}\)
Giải đầy đủ pls
Bài 3
\(\dfrac{55}{23}+\dfrac{-22}{23}\le x\le\dfrac{1}{5}-\dfrac{-1}{6}+\dfrac{79}{30}\) có bao nhiêu số nguyên X thỏa mãn
A 1 B 2 C 3 D 4
Bài 4
Nếu \(\dfrac{-11}{12}< \dfrac{5}{x}< \dfrac{-11}{15}\) Thì x là bao nhiêu
A 5 B 6 C -5 D -6
Bài 5
\(M=\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+\dfrac{1}{3\cdot4}+...+\dfrac{1}{99\cdot100}\)
A 1 B 2 C \(\dfrac{99}{100}\) D \(\dfrac{1}{100}\)
Tìm cặp số nguyên x ; y sao cho :
\(\dfrac{x}{2}\) = \(\dfrac{2}{y}\) - \(\dfrac{11}{6}\)
tìm cặp số nguyên x y sao cho :
\(\dfrac{x}{2}=\dfrac{2}{y}+\dfrac{11}{6}\)
\(\dfrac{1}{5}+\dfrac{2}{11}< \dfrac{x}{55}< \dfrac{2}{5}+\dfrac{1}{5}\) \(\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{6}< x\le\dfrac{13}{4}+\dfrac{14}{8}\)
\(\dfrac{1}{4}+\dfrac{5}{12}+\dfrac{-1}{13}< x< \dfrac{7}{5}+\dfrac{2}{10}+\dfrac{1}{2}\) \(\dfrac{79}{15}+\dfrac{7}{5}+\dfrac{-8}{3}\le x\le\dfrac{10}{3}+\dfrac{15}{4}+\dfrac{23}{12}\)
tìm x
\(\dfrac{3-x}{5-x}=\dfrac{6}{11}\) \(\left(1\dfrac{1}{3}-25\%.x-\dfrac{5}{12}\right)-2x=1,6:\dfrac{3}{5}\)
\(\dfrac{1}{2}.\left(x-\dfrac{2}{3}\right)-\dfrac{1}{3}.\left(2x-3\right)=x\)
\(2.\left(\dfrac{1}{2}-x\right)-3\left(x-\dfrac{1}{3}\right)=\dfrac{7}{2}\)
bài 1: tìm x
(\(\dfrac{5}{6}\) - x + \(\dfrac{7}{12}\)) : (\(\dfrac{11}{24}\) - \(\dfrac{1}{8}\)) = \(\dfrac{11}{36}\)
\(\left(\dfrac{11}{6}-\dfrac{5}{8}\right)\)x\(\dfrac{3}{5}+\dfrac{2}{5}:\dfrac{14}{15}\)