⇒\((x-3).(x-3)=-8.(-2)\)
⇒\((x-3)^2=16\)
⇒\((x-3)^2=4^2=(-4)^2\)
⇒\(x-3\)\(∈\)\(\left\{4;-4\right\}\)
⇒\(x\)\(∈\)\(\left\{7;-1\right\}\)
Vậy \(x\)\(∈\)\(\left\{7;-1\right\}\)
\(\dfrac{3}{2}X-0,2=\dfrac{3}{5}\)
\(\dfrac{1}{3}+x=\dfrac{3}{4}\)
\(1\dfrac{1}{2}x-\dfrac{2}{5}=\dfrac{1}{4}\)
\(\dfrac{11}{8}-\dfrac{3}{8}.x=\dfrac{1}{8}\)
giúp với
Tìm x biết: a) \(\dfrac{6}{-x}=\dfrac{x}{-24}\) b) \(x-\dfrac{7}{12}x+\dfrac{3}{8}x=\dfrac{5}{24}\)
c)\(\left(x-\dfrac{1}{3}\right)^2-\dfrac{1}{2}=1\dfrac{3}{4}\) d) \(\dfrac{x-3}{-2}=\dfrac{-8}{x-3}\)
e) \(\dfrac{9}{x}=\dfrac{-35}{105}\) f) \(\left(x-\dfrac{1}{2}\right)\left(-3-\dfrac{x}{2}\right)=0\)
Bài 4. Tìm x biết:
a. \(\dfrac{x}{5}=\dfrac{2}{5},\dfrac{3}{8}=\dfrac{6}{x},\dfrac{1}{9}=\dfrac{x}{27}\)
b. \(\dfrac{4}{x}=\dfrac{8}{6},\dfrac{3}{x-5}=\dfrac{-4}{x+2},\dfrac{x}{-2}=\dfrac{-8}{x}\)
a) \(\dfrac{-2}{15}\times x=\dfrac{-2}{7}\) b) \(\dfrac{7}{-5}\times x=-3\) c) \(-\dfrac{4}{9}x=\dfrac{1}{2}\) d) \(\dfrac{8}{3}\div x=\dfrac{-3}{8}\)
e) \(x\div\dfrac{3}{-4}=-12\) f) \(\left(-1\right)\div x=\dfrac{-3}{7}+\dfrac{4}{5}\) g)\(\dfrac{4}{11}x-\dfrac{1}{3}=\dfrac{2}{5}\) i) \(\dfrac{-6}{7}-\dfrac{1}{5}x=-4\)
j) \(\dfrac{1}{2}+\dfrac{2}{3}\div7=\dfrac{-1}{3}\) k) \(\dfrac{-5}{2}+x\div7=\dfrac{-1}{3}\) L) \(\dfrac{-3}{2}-\dfrac{1}{4}\div x=-1\)
Tìm x biết:
1/ \(\dfrac{3}{5}-x=0,2\)
2/ \(\dfrac{x}{3}-\dfrac{1}{8}=\dfrac{5}{8}\)
3/ \(3\dfrac{1}{3}.x-6\dfrac{3}{4}=3\dfrac{1}{4}\)
Tìm x biết: a) \(\left(x-\dfrac{1}{2}\right)\left(-3-\dfrac{x}{2}\right)=0\) b) \(x-\dfrac{1}{8}=\dfrac{5}{8}\)
c) \(-\dfrac{1}{2}-\left(\dfrac{3}{2}+x\right)=-2\) d) \(x+\dfrac{1}{3}=\dfrac{-12}{5}.\dfrac{10}{6}\)
Tìm x, biết:
a) x+\(\dfrac{1}{6}\)=\(\dfrac{-3}{8}\) b) \(2-\left(\dfrac{3}{4}-x\right)=\dfrac{7}{12}\)
c) \(\dfrac{1}{2}x\)+\(\dfrac{1}{8}x=\dfrac{3}{4}\) d) 75%-\(1\dfrac{1}{2}+0,5:\dfrac{5}{12}-\left(\dfrac{-1}{2}\right)^2\)
a) \(\dfrac{2}{7}-\dfrac{8}{9}.x=\dfrac{2}{3}\)
b) \(\dfrac{2}{5}-\dfrac{2}{5}x=\dfrac{2}{5}\)
c) \(\dfrac{2}{9}-\dfrac{7}{8}x=\dfrac{1}{3}\)
a) \(\dfrac{-11}{15}< \dfrac{x}{15}< \dfrac{-8}{15}\)
b) \(\dfrac{3}{7}< \dfrac{x}{21}< \dfrac{2}{3}\)
c) \(\dfrac{-67}{21}< \dfrac{x}{168}< \dfrac{-3}{8}\)
tìm x
\(x-\dfrac{1}{2}=\dfrac{3}{4}\)
\(x+\dfrac{7}{8}=\dfrac{3}{4}\)
\(\dfrac{1}{2}.x-\dfrac{1}{4}=\dfrac{-1}{2}\)
\(\dfrac{1}{2}-\dfrac{5}{6}:x=\dfrac{2}{3}\)
