Question

\(\dfrac{a-2}{8a^2-8a}\)+\(\dfrac{a+1}{6a^3-6a^2}\)

Answer 1

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Answer 2

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Answer 3

\(\dfrac{a-2}{8a^2-8a}+\dfrac{a+1}{6a^3-6a^2}=\dfrac{a-2}{8a\left(a-1\right)}+\dfrac{a+1}{6a^2\left(a-1\right)}=\dfrac{3a\left(a-2\right)}{24a^2\left(a-1\right)}+\dfrac{4\left(a+1\right)}{24a^2\left(a-1\right)}=\dfrac{3a^2-6a}{24a^2\left(a-1\right)}+\dfrac{4a+4}{24a^2\left(a-1\right)}=\dfrac{3a^2-6a+4a+4}{24a^2\left(a-1\right)}=\dfrac{3a^2-2a+4}{24a^2\left(a-1\right)}\)