\(\dfrac{81^2.125^3}{5^4.\left(-27\right)^4}=\dfrac{\left(3^4\right)^2.\left(5^3\right)^2}{5^4.\left(3^3\right)^4}=\dfrac{3^8.5^6}{5^4.3^{12}}=\dfrac{5^2}{3^4}=\dfrac{25}{81}\)
\(\dfrac{81^2.125^3}{5^4.\left(-27\right)^4}=\dfrac{\left(3^4\right)^2.\left(5^3\right)^2}{5^4.\left(3^3\right)^4}=\dfrac{3^8.5^6}{5^4.3^{12}}=\dfrac{5^2}{3^4}=\dfrac{25}{81}\)
a,2.(\(\dfrac{1}{4}\)+x)\(^3\)=(\(-\dfrac{27}{4}\))
b,(x+\(\dfrac{1}{2}\))\(^3\):3=\(\dfrac{-1}{81}\)
c,(\(\dfrac{2}{3}\)-x)\(^2\)=1:\(\dfrac{4}{9}\)
d,(2x-\(\dfrac{1}{5}\))\(^2\)+\(\dfrac{16}{25}\)=1
e,(\(\dfrac{2}{5}\)-3x)\(^2\)-\(\dfrac{1}{5}\)=\(\dfrac{4}{25}\)
\(\dfrac{8^{14}}{4^4.64^5}\)
\(\dfrac{9^{10}.27^7}{81^7.3^{15}}\)
\(\left(\dfrac{3}{10}\right)^4.\left(0,3\right)^5.\left(\dfrac{10}{3}\right)^{10}\)
\(\dfrac{\left(4^3\right)^2.9^4}{6^7.8^2}\)
\(\dfrac{4^8.9^4}{6^6.8^3}\)
\(3^6.\left(\dfrac{1}{3}\right)^6.81^2.\dfrac{1}{27^2}\) TÍNH
Tính
a)\((\dfrac{3}{4}-81).(\dfrac{3^2}{5}-81).(\dfrac{3^3}{6}-81)...(\dfrac{3^{2000}}{2003}-81)\)
b)\(\dfrac{69}{157}-(2+(3+(4+5^{-1})^{-1})^{-1}\)
bài 6: tính :
\(\dfrac{10^9.\left(-81\right)^{10}}{\left(-8\right)^4.25^5.9^{10}}\)
b,\(\dfrac{9^4.\left(-4\right)^5.25^3}{8^3,\left(-27\right)^2.5^7}\)
c,\(\dfrac{3^{186}.\left(-25\right)^{50}}{\left(-15\right)^{100}.27^{29}}\)
\(99^{99}\)-\(\left\{1,\left(3\right)-\left[5\times2^3-\left(-7^2\right)+\dfrac{1}{3}+99^9\times\left(27^4-81^3-99^{90}\right)\right]\right\}\)
Tính:
\(\left(\dfrac{3}{4}-81\right).\left(\dfrac{3^2}{5}-81\right).\left(\dfrac{3^3}{6}-81\right).....\left(\dfrac{3^{2000}}{2003}-81\right)\)
\(\sqrt{\dfrac{4}{81}}:\sqrt{\dfrac{25}{81}}-1\dfrac{3}{5}\)
(3/5)mũ 5 . x = (3/7)mũ 7
(-1/3)mũ 3 . x = 1/81
(x - 1/2) mũ 3 = 1/27
(3x + 1)mũ 3 = -27
(x + 1/2) mũ 4 = 16/81
(4/5) mũ 5.x = (4/5) mũ 7
\(\left(3-x\right)^3=-\dfrac{27}{64};\left(x-5\right)^3=\dfrac{1}{-27};\left(x-\dfrac{1}{2}\right)^3=\dfrac{27}{8};\left(2x-1\right)^2=\dfrac{1}{4};\left(2-3x\right)^2=\dfrac{9}{4};\left(1-\dfrac{2}{3}\right)^2=\dfrac{4}{9}\)
\(\dfrac{4^5.9^4}{8^3.27^3}\);\(\dfrac{4^{20}.3^{35}}{2^{37}.27^{12}}\)\(;\dfrac{5^4.20^4}{25^5.4^5};\dfrac{2^{15}.9^4}{6^6.8^3}\)