$\frac {7}{12} - \frac{27}{7} \times \frac {1}{18}$
$ = \frac{7}{12} - \frac{3}{7} \times \frac{1}{2}$
$ = \frac{7}{12} - \frac{3}{14}$
$ = \frac{49}{84} - \frac{18}{84}$
$ = \frac{31}{84}$
$\frac {7}{12} - \frac{27}{7} \times \frac {1}{18}$
$ = \frac{7}{12} - \frac{3}{7} \times \frac{1}{2}$
$ = \frac{7}{12} - \frac{3}{14}$
$ = \frac{49}{84} - \frac{18}{84}$
$ = \frac{31}{84}$
1.0,25.x+\(\dfrac{7}{12}\)=\(\dfrac{13}{18}-\dfrac{1}{9}\)
\(\dfrac{8}{7}:\) (\(\dfrac{2}{9}-\dfrac{1}{18}\) ) + \(\dfrac{7}{8}:\) (\(\dfrac{1}{36}-\dfrac{5}{12}\) )
\(d,\dfrac{\left(13\dfrac{1}{4}-2\dfrac{5}{27}-10\dfrac{5}{6}\right).230\dfrac{1}{25}+46\dfrac{3}{4}}{\left(1\dfrac{3}{7}+\dfrac{10}{3}\right):\left(12\dfrac{1}{3}-14\dfrac{2}{7}\right)}\)
a) \(\dfrac{3x-7}{3}=\dfrac{-27}{7-3x}\)
b) \(\dfrac{3x+5}{12}=\dfrac{3}{5+3x}\)
a) \(\dfrac{15}{11}\) - (\(\dfrac{5}{7}\) - \(\dfrac{18}{11}\)) + \(\dfrac{27}{7}\)
b) \(\dfrac{39}{5}\)+ (\(\dfrac{9}{4}\) - \(\dfrac{9}{5}\)) - (\(\dfrac{5}{4}\) + 1,2)
c) -1,2 - 0,8 + 0,25 + 5,75 - 2022
d) 0,1 + \(\dfrac{16}{9}\) + 5,1 + \(\dfrac{-20}{9}\)
Bài 1: Thực hiện phép tính sau:
\(a,\dfrac{9}{18}-\dfrac{-7}{12}+\dfrac{13}{32}\)
\(b,\dfrac{5}{-8}+\dfrac{14}{25}-\dfrac{6}{10}\)
tính)
a) \(\dfrac{3}{4}+\dfrac{-7}{12}-\dfrac{2}{3}\)
b) \(15\dfrac{5}{6}+\left(\dfrac{17}{18}-\dfrac{5}{12}\right)\)
Tìm x, biết:
a) \(\dfrac{-1}{10}\) + \(\dfrac{2}{5}\)x + \(\dfrac{7}{20}\) = \(\dfrac{1}{10}\)
b) \(\dfrac{1}{3}\) + \(\dfrac{1}{2}\) : x= \(-\dfrac{1}{5}\)
c) \(-\dfrac{2}{3}\) : x + \(\dfrac{5}{8}\) = \(-\dfrac{7}{12}\)
Tìm x, biết:
a) \(\dfrac{1}{20}\) - (x - \(\dfrac{8}{5}\)) = \(\dfrac{1}{10}\)
b) \(\dfrac{7}{4}\) - (x + \(\dfrac{5}{3}\)) = \(\dfrac{-12}{5}\)
c) x - [\(\dfrac{17}{2}\) - \(\left(\dfrac{-3}{7}+\dfrac{5}{3}\right)\)] = \(\dfrac{-1}{3}\)
a \(\dfrac{-4}{7}\) - \(\dfrac{5}{13}\) x \(\dfrac{-39}{25}\) + \(\dfrac{-1}{42}\) : \(\dfrac{-5}{6}\)
b \(\dfrac{2}{9}\) x [\(\dfrac{4}{45}\): ( \(\dfrac{1}{5}\) - \(\dfrac{2}{15}\)) + 1\(\dfrac{2}{3}\)] - \(\dfrac{-5}{27}\)