\(\dfrac{5}{6}.18\dfrac{2}{3}-\dfrac{5}{6}.6\dfrac{2}{3}=\dfrac{5}{6}\left(18\dfrac{2}{3}-6\dfrac{2}{3}\right)=\dfrac{5}{6}.12=10\)
\(=\left(18\dfrac{2}{3}-6\dfrac{2}{3}\right).\dfrac{5}{6}=\dfrac{5}{6}.12=10\)
\(\dfrac{5}{6}.18\dfrac{2}{3}-\dfrac{5}{6}.6\dfrac{2}{3}=\dfrac{5}{6}\left(18\dfrac{2}{3}-6\dfrac{2}{3}\right)=\dfrac{5}{6}.12=10\)
\(=\left(18\dfrac{2}{3}-6\dfrac{2}{3}\right).\dfrac{5}{6}=\dfrac{5}{6}.12=10\)
a, 1\(\dfrac{5}{18}\)+\(\dfrac{7}{25}\)-\(\dfrac{5}{18}\)+\(\dfrac{18}{25}\)-0, 75
b, \(\dfrac{2}{5}\).\(\dfrac{1}{3}\)-\(\dfrac{4}{3}\).\(\dfrac{2}{5}\)
c, (\(\dfrac{-1}{4}\)).( 6\(\dfrac{2}{11}\)) + 3 \(\dfrac{9}{11}\).(\(\dfrac{-1}{4}\))
d, 4. (-\(\dfrac{1}{2}\))\(^{3_{ }}\)-\(_{ }\)2. (\(\dfrac{-1}{2}\))\(^2\) + 3. (\(\dfrac{-1}{2}\)) + 1
e, \(\dfrac{1}{6}\)-(\(\dfrac{2}{3}\))\(^2\) + \(\dfrac{5}{18}\)
f, (\(\dfrac{4}{3}\)-\(\dfrac{3}{2}\))\(^2\)- 2.|-\(\dfrac{1}{9}\)| + (-\(\dfrac{5}{18}\))
\(\dfrac{15}{12}+\dfrac{5}{13}-\dfrac{3}{12}-\dfrac{18}{13}-\dfrac{1}{3}\)
\(14.\dfrac{3}{2}+\dfrac{6}{5}:\left(\dfrac{-2}{5}\right)\)
\(\sqrt{\dfrac{1}{4}+\dfrac{2}{3}-\left(\dfrac{1}{3}\right)^2}\)
tính)
a) \(\dfrac{3}{4}+\dfrac{-7}{12}-\dfrac{2}{3}\)
b) \(15\dfrac{5}{6}+\left(\dfrac{17}{18}-\dfrac{5}{12}\right)\)
tính hợp lí
a,\(\dfrac{27}{2}\) x 7,5 + \(\dfrac{27}{2}\) x 2,5 -150
b,3\(^3\)x \(\dfrac{18}{5}\) - 3\(^3\) x 2\(\dfrac{2}{5}\) - 3\(^3\) x \(\dfrac{6}{5}\)
tính một cách hợp lí
f) \(\dfrac{15^3+5.15^2-5^3}{18^3+6.18^2-6^3}\) g) \(\left(\dfrac{-3}{4}+\dfrac{2}{5}\right):\dfrac{3}{7}+\left(\dfrac{3}{5}+\dfrac{-1}{4}\right):\dfrac{3}{7}\)
\(\dfrac{1}{6}-\left(\dfrac{2}{3}\right)^2+\dfrac{5}{18}\)
a)\(0,5+\dfrac{1}{3}+0,4+\dfrac{5}{7}-\dfrac{1}{6}-\dfrac{4}{35}\)
b)\(\left(3-\dfrac{1}{4}+\dfrac{2}{3}\right)-\left(5+\dfrac{1}{3}-\dfrac{6}{5}\right)-\left(-6-\dfrac{7}{4}+\dfrac{3}{2}\right)\)
c)\(\dfrac{1}{3}-\dfrac{3}{4}-\left(-\dfrac{3}{5}\right)+\dfrac{1}{64}-\dfrac{2}{9}-\dfrac{1}{36}+\dfrac{1}{15}\)
\(15\dfrac{5}{6}+\left(\dfrac{17}{18}-\dfrac{5}{12}\right):3\dfrac{1}{6}\)
tính
Tính nhanh:
\(a,A=\dfrac{\dfrac{5}{4}+\dfrac{5}{5}+\dfrac{5}{7}-\dfrac{5}{11}}{\dfrac{10}{4}+\dfrac{10}{5}+\dfrac{10}{7}-\dfrac{10}{11}}\)\(b,B=\dfrac{2+\dfrac{6}{5}-\dfrac{6}{7}-\dfrac{6}{11}}{\dfrac{2}{3}+\dfrac{2}{5}-\dfrac{2}{7}-\dfrac{2}{11}}\)
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