\(\dfrac{5}{6}+\dfrac{5}{6}=\dfrac{5+5}{6}=\dfrac{10}{6}=\dfrac{10:2}{6:2}=\dfrac{5}{3}\)
\(\dfrac{3}{5}+\dfrac{1}{2}+\dfrac{8}{15}\)
\(\dfrac{6}{9}+\dfrac{14}{18}-\dfrac{5}{6}\)
\(\dfrac{9}{20}-\dfrac{3}{5}:\dfrac{4}{1}\)
\(\dfrac{1}{6}+\dfrac{2}{3}\) x \(\dfrac{8}{9}\)
A,\(\dfrac{3}{5}+\dfrac{1}{6}\)
B,\(4+\dfrac{2}{5}\)
C,\(\dfrac{25}{12}-\dfrac{7}{6}\)
D,\(\dfrac{9}{7}-\dfrac{7}{6}\)
E,\(\dfrac{3}{7}\) x \(\dfrac{2}{5}\)
\(a.\dfrac{3}{5}\) x \(\dfrac{17}{21}\) \(+ \) \(\dfrac{17}{21}\) x \(\dfrac{2}{5}\)
\(b.(\dfrac{8}{5}+\dfrac{5}{6}):\dfrac{7}{6}\)
Tính theo cách thuận tiện :
\(\dfrac{13}{7}+\dfrac{5}{6}+\dfrac{2}{7}+\dfrac{7}{6}\) = ?
\(\dfrac{1}{2}x\dfrac{5}{6}+\dfrac{1}{2}x\dfrac{11}{6}=?\)
Đặt tính rồi tính :
\(a.\dfrac{5}{6}+\dfrac{2}{5}\)
\(b.\dfrac{6}{5}-\dfrac{3}{4}\)
\(c.\dfrac{9}{16}\times\dfrac{4}{3}\)
\(d.\dfrac{8}{17}:6\)
a,\(\dfrac{5}{8}\)+\(\dfrac{1}{4}\)\(-\)\(\dfrac{5}{6}\)
b,\(\dfrac{6}{11}\):\(\dfrac{3}{5}\)\(-\)\(\dfrac{2}{3}\)
\(\dfrac{3}{7}\) + 4 = ?
\(\dfrac{5}{9}\) x 3 = ?
\(\dfrac{7}{8}\) - \(\dfrac{2}{9}\)= ?
5 - \(\dfrac{3}{4}\)= ?
\(\dfrac{5}{7}\) : 6 = ?
\(\dfrac{5}{6}\) x \(\dfrac{2}{7}\)= ?
3 + \(\dfrac{3}{4}\)= ?
\(\dfrac{3}{5}x\dfrac{4}{8}\) = ?
5 : \(\dfrac{3}{8}\)= ?
Mong mn trả lời
Sắp sếp theo giảm dần
\(\dfrac{5}{7}\);\(\dfrac{6}{11}\);\(\dfrac{6}{5}\);\(\dfrac{6}{7}\)
a,\(\dfrac{2}{3}\)x\(\dfrac{5}{2}\):\(\dfrac{9}{5}\)
b,\(\dfrac{1}{3}\)x\(\dfrac{1}{4}\)+\(\dfrac{5}{6}\)
c,\(\dfrac{1}{2}\)-\(\dfrac{7}{8}\):\(\dfrac{7}{4}\)
d,\(\dfrac{6}{5}\)-\(\dfrac{4}{5}\)x\(\dfrac{3}{2}\)
