Question

\(\dfrac{3}{2}\)-(\(\dfrac{1}{2}\)+\(\dfrac{1}{4}\)) là 

Answer 1

\(\dfrac{3}{2}-\left(\dfrac{1}{2}+\dfrac{1}{4}\right)=\dfrac{6}{4}-\left(\dfrac{2}{4}+\dfrac{1}{4}\right)=\dfrac{6}{4}-\dfrac{3}{4}=\dfrac{3}{4}\)

Answer 2

\(\dfrac{3}{2}-(\dfrac{1}{2}+\dfrac{1}{4})=\dfrac{3}{2}-(\dfrac{2}{4}+\dfrac{1}{4})=\dfrac{3}{2}-\dfrac{3}{4}= \dfrac{6}{4}-\dfrac{3}{4}=\dfrac{3}{4}\)

Answer 3

= 3/2 - ( 2/4 + 1/4 )

=     3/2  -  3/4

=     6/4 - 3/4

=          1/2