ĐKXĐ: \(x\notin\left\{3;-3\right\}\)
\(\dfrac{2x+1}{x-3}-\dfrac{x}{x+3}=1\)
=>\(\dfrac{\left(2x+1\right)\left(x+3\right)-x\left(x-3\right)}{\left(x-3\right)\left(x+3\right)}=1\)
=>\(2x^2+6x+x+3-x^2+3x=x^2-9\)
=>\(x^2+10x+3=x^2-9\)
=>10x+3=-9
=>10x=-12
=>\(x=-\dfrac{12}{10}=-\dfrac{6}{5}\left(nhận\right)\)