\(\dfrac{2^7.9^3.2020^0}{3^5.8^2}=\dfrac{2^7.\left(3^2\right)^3.1}{3^5.\left(2^2\right)^2.2^2}=\dfrac{2^7.3^6.1}{3^5.2^4.2^2}=\dfrac{2^7.3^5.3.1}{3^5.2^6}=\dfrac{2^6.2.3.1}{2^6}=2.3.1=6\)
\(\dfrac{2^7.9^3.2020^0}{3^5.8^2}=\dfrac{2^7.\left(3^2\right)^3.1}{3^5.\left(2^2\right)^2.2^2}=\dfrac{2^7.3^6.1}{3^5.2^4.2^2}=\dfrac{2^7.3^5.3.1}{3^5.2^6}=\dfrac{2^6.2.3.1}{2^6}=2.3.1=6\)
\(\dfrac{2^7.9^3}{6^5.8^2}\)
a) \(\dfrac{2^7.9^3}{6^5.8^2}\)
b) \(\dfrac{\left(0,6\right)^5}{\left(0,2\right)^6}\)
tính GTBT sau
2^7.9^3/6^5.8^2
GIÚP MK VS NHÉ CÁC P
2^7.9^3
6^5.8^2
1. Tính
\(\frac{2^7.9^3}{6^5.8^2}\)
2. Tìm x
\(8^x:4^x=4\)
3. So sánh
\(222^{555}va555^{222}\)
Giúp mình nha
Tìm giá trị của biểu thức sau :2^7.9^3/6^5.8^2
Tìm giá trị của biểu thức sau :
a) \(\frac{2^7.9^3}{6^5.8^2}\)
b) \(\frac{6^3+3.6^2+3^3}{-13}\)
GIÚP MK VỚI
rut gon :
\(\frac{2^7.9^3}{6^5.8^2}\)
2^7.9^3
6^5.8^2
\(\frac{2^7.9^3}{6^5.8^2}=.....=........=......=....=.....\)