\(x+\dfrac{4}{9}+\dfrac{8}{18}+\dfrac{12}{27}+\dfrac{16}{36}=\dfrac{16}{9}\)
giúp mk với ạ
khoanh vào phân số bằng \(\dfrac{4}{9}\) \(\dfrac{12}{18}\), \(\dfrac{6}{10}\), \(\dfrac{16}{27}\), \(\dfrac{24}{54}\), \(\dfrac{20}{36}\)
Rút gọn rồi tính:
\(\dfrac{20}{12}+\dfrac{36}{18}-\dfrac{21}{28}=?\)
Tính
a.\(\dfrac{4}{9}+\dfrac{3}{7}\) \(\dfrac{3}{4}+\dfrac{7}{24}\) \(\dfrac{1}{3}+\dfrac{2}{9}+\dfrac{4}{27}\)
b.\(\dfrac{5}{6}-\dfrac{3}{8}\) \(\dfrac{7}{15}-\dfrac{11}{30}\) \(\dfrac{2}{3}+\dfrac{1}{6}-\dfrac{7}{12}\)
c.\(\dfrac{18}{25}\times\dfrac{15}{6}\) \(\dfrac{30}{49}:\dfrac{6}{7}\) \(\dfrac{1}{2}\times\dfrac{3}{4}:\dfrac{6}{5}\)
d.\(8\times\dfrac{3}{5}:\dfrac{12}{5}\) \(4:\dfrac{9}{5}:\dfrac{10}{3}\)
3 bn đầu tiên xong mik sẽ tick
\(a,\dfrac{9}{12}=\dfrac{3}{...}=\dfrac{...}{36}\\ b,\dfrac{4}{6}=\dfrac{10}{...}=\dfrac{...}{3}\)
bài 2:
\(\dfrac{11}{12}\)-\(\dfrac{5}{12}\)=...... \(\dfrac{25}{24}\)-\(\dfrac{16}{24}\)=...... \(\dfrac{27}{36}\)-\(\dfrac{15}{36}\)=.......
3. Điền số thích hợp vào chỗ chấm:
a) \(\dfrac{5}{6}=\dfrac{10}{.....}=\dfrac{.......}{36}\)
b) \(\dfrac{9}{12}=\dfrac{6}{.....}=\dfrac{....}{20}\)
Giải và giải thích
Phân số \(\dfrac{4}{9}\)bằng phân số nào dưới đây:
a. \(\dfrac{8}{27}\)
b. \(\dfrac{16}{27}\)
c. \(\dfrac{12}{18}\)
d. \(\dfrac{12}{27}\)
2.Tính giá trị biểu thức
a) ( 42 - \(\dfrac{5}{6}\) x \(\dfrac{36}{5}\)) : \(\dfrac{1}{2}\) + \(\dfrac{7}{6}\) b) \(\dfrac{18}{5}\) - \(\dfrac{1}{7}\) x 2 + \(\dfrac{1}{3}\)