Các câu hỏi tương tự
8 tháng 3 2022 lúc 17:09
Tìm x:
\(\dfrac{1}{3}\) + \(\dfrac{1}{6}\)+ \(\dfrac{1}{10}\)+ ...+ \(\dfrac{1}{xx\left(x+1\right):2}\)= \(\dfrac{2017}{2019}\)
Mọ người giúp em với ạ! Em cảm ơn!
Tính:
a) (6 : dfrac{3}{5} 1dfrac{1}{6} x dfrac{6}{7} ) : ( 4dfrac{1}{5} x dfrac{10}{11} + 5dfrac{2}{11} )
b) (1-dfrac{1}{2}) x (1-dfrac{1}{3}) x (1-dfrac{1}{4}) x ..... x (1-dfrac{1}{2003}) x (1-dfrac{1}{2007})
Đọc tiếp
Tính:
a) (6 : \(\dfrac{3}{5}\) \(1\dfrac{1}{6}\) x \(\dfrac{6}{7}\) ) : ( \(4\dfrac{1}{5}\) x \(\dfrac{10}{11}\) + \(5\dfrac{2}{11}\) )
b) (\(1-\dfrac{1}{2}\)) x (\(1-\dfrac{1}{3}\)) x (\(1-\dfrac{1}{4}\)) x ..... x (\(1-\dfrac{1}{2003}\)) x (\(1-\dfrac{1}{2007}\))
Bài 3 Tìm x
\(\dfrac{1}{2}:3+x=1\dfrac{2}{3}\)
\(2\dfrac{3}{4}-x=\dfrac{5}{6}+\dfrac{2}{3}\)
\(5\dfrac{4}{10}-x\) X\(\dfrac{3}{4}=\dfrac{2}{3}\)
\(\dfrac{\left(\dfrac{1}{6}+\dfrac{1}{10}+\dfrac{1}{15}\right):\left(\dfrac{1}{6}+\dfrac{1}{10}-\dfrac{1}{15}\right)}{\left(\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{4}-\dfrac{1}{5}\right):\left(\dfrac{1}{4}-\dfrac{1}{6}\right)}=\)
dfrac{15}{14} : dfrac{10}{21} x dfrac{1}{5}
5 x dfrac{1}{5} + dfrac{1}{5}
7 : dfrac{1}{5} - dfrac{1}{5}
6 + dfrac{1}{5} : 2
8 - dfrac{1}{5} x 7
Đọc tiếp
\(\dfrac{15}{14}\) : \(\dfrac{10}{21}\) x \(\dfrac{1}{5}\)
\(5\) x \(\dfrac{1}{5}\) + \(\dfrac{1}{5}\)
\(7\) : \(\dfrac{1}{5}\) - \(\dfrac{1}{5}\)
\(6\) + \(\dfrac{1}{5}\) : \(2\)
\(8\) - \(\dfrac{1}{5}\) x \(7\)
\(1-(6\dfrac{2}{5}+x-5\dfrac{3}{10})\div8\dfrac{1}{10}=0\)
Giúp mình đi mình cần gấp lắm!
a) \(\dfrac{1}{2}x\dfrac{1}{3}+y=\dfrac{3}{4}\) b)\(\dfrac{1}{2}x\dfrac{1}{5}+y=\dfrac{3}{10}\)
20 tháng 9 2023 lúc 19:17
\(3\dfrac{7}{8}\times x-2\dfrac{3}{4}=3\dfrac{6}{12}\times\dfrac{10}{8}-\dfrac{1}{3}\)
Tìm x
Bài 5: (Đề 2) Tính
a) \(2-1\dfrac{5}{6}+2\dfrac{2}{3}\)=........
b) \(\dfrac{5}{9}x\left(2\dfrac{5}{6}-1\dfrac{2}{3}\right)\)=..........
c)\(1\dfrac{1}{3}:\left(2+1\dfrac{1}{6}:2\dfrac{5}{6}\right)\)=..........
d) \(2\dfrac{3}{5}:\dfrac{3}{4}x1\dfrac{4}{5}\) =..........