Câu hỏi của Vũ Ngọc Diệp

Question

$\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{12}+\dfrac{1}{20}+\dfrac{1}{30}=$

Pythagoras · Accepted Answer

$\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}$$=\left(\frac{1}{2}+\frac{1}{20}\right)+\left(\frac{1}{6}+\frac{1}{30}\right)+\frac{1}{12}$$=\frac{11}{20}+\frac{1}{5}+\frac{1}{12}$$=\frac{3}{4}+\frac{1}{12}$$=\frac{10}{12}=\frac{5}{6}$Câu trả lời: $\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}$$=\left(\frac{1}{2}+\frac{1}{20}\right)+\left(\frac{1}{6}+\frac{1}{30}\right)+\frac{1}{12}$$=\frac{11}{20}+\frac{1}{5}+\frac{1}{12}$$=\frac{3}{4}+\frac{1}{12}$$=\frac{10}{12}=\frac{5}{6}$

Bùi Hải Hà My · Answer

= 5 / 6 nhéCâu trả lời: = 5 / 6 nhé

💖꧁༺ɦắ☪☠Áℳ༻꧂💖 · Answer

bằng 0.83333333333nha hok tốt nhaok nhaaaaaaaaok okCâu trả lời: bằng 0.83333333333nha hok tốt nhaok nhaaaaaaaaok ok

\(\dfrac{1}{2}\) + \(\dfrac{1}{12}\)	2 + \(\dfrac{1}{6}\)	\(\dfrac{1}{20}\)	1 - \(\dfrac{1}{9}\)
\(\dfrac{1}{15}\) + \(\dfrac{2}{15}\)	\(\dfrac{1}{2}\) + \(\dfrac{2}{3}\)	\(\dfrac{7}{12}\)	\(\dfrac{4}{12}\)
\(\dfrac{9}{14}\)+ \(\dfrac{1}{14}\)	1 + \(\dfrac{1}{6}\)	\(\dfrac{1}{4}\) - \(\dfrac{1}{5}\)	\(\dfrac{1}{3}\) - \(\dfrac{2}{9}\)
\(\dfrac{3}{2}\) + \(\dfrac{2}{3}\)	\(\dfrac{1}{5}\)	1 - \(\dfrac{8}{9}\)
\(\dfrac{5}{7}\)	1 - \(\dfrac{2}{3}\)	\(\dfrac{1}{3}\) + \(\dfrac{5}{9}\)

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