\(=\dfrac{1}{2}\times\dfrac{1}{2}\times6=\dfrac{1}{2}\times3=\dfrac{3}{2}\)
\(=\dfrac{6}{4}=\dfrac{3}{2}\)
= \(\dfrac{1}{2}\) x \(\dfrac{1}{2}\) x 6 = \(\dfrac{1}{2}\) x 3 = \(\dfrac{3}{2}\)
\(=\dfrac{1}{2}\times\dfrac{1}{2}\times6=\dfrac{1}{2}\times3=\dfrac{3}{2}\)
\(=\dfrac{6}{4}=\dfrac{3}{2}\)
= \(\dfrac{1}{2}\) x \(\dfrac{1}{2}\) x 6 = \(\dfrac{1}{2}\) x 3 = \(\dfrac{3}{2}\)
a,\(\dfrac{2}{3}\)x\(\dfrac{5}{2}\):\(\dfrac{9}{5}\)
b,\(\dfrac{1}{3}\)x\(\dfrac{1}{4}\)+\(\dfrac{5}{6}\)
c,\(\dfrac{1}{2}\)-\(\dfrac{7}{8}\):\(\dfrac{7}{4}\)
d,\(\dfrac{6}{5}\)-\(\dfrac{4}{5}\)x\(\dfrac{3}{2}\)
Tính theo cách thuận tiện :
\(\dfrac{13}{7}+\dfrac{5}{6}+\dfrac{2}{7}+\dfrac{7}{6}\) = ?
\(\dfrac{1}{2}x\dfrac{5}{6}+\dfrac{1}{2}x\dfrac{11}{6}=?\)
\(\dfrac{3}{5}+\dfrac{1}{2}+\dfrac{8}{15}\)
\(\dfrac{6}{9}+\dfrac{14}{18}-\dfrac{5}{6}\)
\(\dfrac{9}{20}-\dfrac{3}{5}:\dfrac{4}{1}\)
\(\dfrac{1}{6}+\dfrac{2}{3}\) x \(\dfrac{8}{9}\)
2.Tính giá trị biểu thức
a) ( 42 - \(\dfrac{5}{6}\) x \(\dfrac{36}{5}\)) : \(\dfrac{1}{2}\) + \(\dfrac{7}{6}\) b) \(\dfrac{18}{5}\) - \(\dfrac{1}{7}\) x 2 + \(\dfrac{1}{3}\)
Tìm x :
a) \(\dfrac{2}{9}\) + x = 1 b)\(\dfrac{6}{7}\) - x = \(\dfrac{2}{3}\) c)x - \(\dfrac{1}{2}\)= \(\dfrac{1}{4}\)
Bài 1: Tính
a) \(\dfrac{9}{5}+\dfrac{2}{5}\) x \(\dfrac{4}{6}\) b) \(\dfrac{3}{8}\) x 2 - \(\dfrac{6}{7}\) x \(\dfrac{1}{3}\)
Bài 2: Tính bằng cách thuận tiện nhất:
a) \(\dfrac{11}{23}+\dfrac{2}{23}+\dfrac{9}{23}+\dfrac{18}{23}\) b)\(\dfrac{25}{12}+\dfrac{17}{6}-\dfrac{15}{36}-\dfrac{15}{6}\)
Bài 3: Một hình chữ nhật có chiều rộng là \(\dfrac{3}{5}\) m và bằng một nửa chiều dài. Tính diện tích hình chữ nhật đó.
tìm số tự nhin x bt
a.\(x-\)\(\dfrac{5}{14}=\dfrac{3}{7}-\dfrac{1}{14}\) b.\(\dfrac{2}{9}:x=\dfrac{1}{2}+\dfrac{2}{3}\) c.\(\dfrac{6}{32:x}=\dfrac{12}{16}\)
Y x \(\dfrac{1}{2}\) + Y x \(\dfrac{1}{6}\) + Y x \(\dfrac{1}{12}\) + Y x \(\dfrac{1}{20}\) = \(\dfrac{8}{5}\)
Tính bằng cách thuận tiện nhất :
( 1 - \(\dfrac{1}{2}\) ) x ( 1 - \(\dfrac{1}{3}\) ) x ( 1 - \(\dfrac{1}{4}\) ) x ( 1 - \(\dfrac{1}{5}\) ) x ( 1 - \(\dfrac{1}{6}\) )