\(\dfrac{1}{15}+\dfrac{2}{15}=\dfrac{3}{15}=\dfrac{1}{5}\)
\(\dfrac{1}{15}+\dfrac{2}{15}=\dfrac{3}{15}=\dfrac{1}{5}\)
VÒNG 2
Bài 1: Mèo con nhanh nhẹn
\(\dfrac{1}{2}\) + \(\dfrac{1}{12}\) | 2 + \(\dfrac{1}{6}\) | \(\dfrac{1}{20}\) | 1 - \(\dfrac{1}{9}\) | |
\(\dfrac{1}{15}\) + \(\dfrac{2}{15}\) | \(\dfrac{1}{2}\) + \(\dfrac{2}{3}\) | \(\dfrac{7}{12}\) | \(\dfrac{4}{12}\) | |
\(\dfrac{9}{14}\)+ \(\dfrac{1}{14}\) | 1 + \(\dfrac{1}{6}\) | \(\dfrac{1}{4}\) - \(\dfrac{1}{5}\) | \(\dfrac{1}{3}\) - \(\dfrac{2}{9}\) | |
\(\dfrac{3}{2}\) + \(\dfrac{2}{3}\) | \(\dfrac{1}{5}\) | 1 - \(\dfrac{8}{9}\) | ||
\(\dfrac{5}{7}\) | 1 - \(\dfrac{2}{3}\) | \(\dfrac{1}{3}\) + \(\dfrac{5}{9}\) |
\(\dfrac{\left(\dfrac{1}{6}+\dfrac{1}{10}+\dfrac{1}{15}\right):\left(\dfrac{1}{6}+\dfrac{1}{10}-\dfrac{1}{15}\right)}{\left(\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{4}-\dfrac{1}{5}\right):\left(\dfrac{1}{4}-\dfrac{1}{6}\right)}=\)
a. Tìm a, biết: 1 - ( 5\(\dfrac{4}{9}\) + a - 7\(\dfrac{7}{18}\) ) : 15\(\dfrac{3}{4}\) = 0
b. Tính b = ( \(\dfrac{2}{15}\) + \(\dfrac{5}{3}\) - \(\dfrac{3}{5}\) ) : ( \(4\dfrac{2}{3}\) - \(2\dfrac{1}{2}\) )
\(6\dfrac{1}{2}\) - \(2\dfrac{1}{3}\) : \(\dfrac{7}{15}\)
Tính thuận tiện : \(\dfrac{15}{7}:\dfrac{1}{2}+\dfrac{3}{14}:\dfrac{1}{2}\)
Tính nhanh
a, S= \(\dfrac{1}{3}\) + \(\dfrac{1}{15}\) + \(\dfrac{1}{35}\) + \(\dfrac{1}{63}\) + \(\dfrac{1}{99}\) + \(\dfrac{1}{143}\)
b, A = \(\dfrac{1}{3}\) + \(\dfrac{1}{6}\) + \(\dfrac{1}{10}\) + \(\dfrac{1}{15}\) + \(\dfrac{1}{21}\) + \(\dfrac{1}{28}\)
c, H =\(\dfrac{4047991-2010x2009}{4050000-2011x2009}\)
d, T = \(\dfrac{2009x20010+2000}{2011x2010-2020}\)
e, P = \(\dfrac{7589-80,5x69,3}{7485,05-79x69,3}\)
f, B = 5,1 x 42,2 + 1,7 x 448 x 3 - 0,15 x 700
Giúp mình với
Tìm x biết: (\(\dfrac{2}{15}\)+\(\dfrac{2}{35}\)+\(\dfrac{2}{63}\)):x= \(\dfrac{1}{18}\)..
Tìm X
X:3\(\dfrac{1}{15}\)-\(\dfrac{3}{4}\)=2\(\dfrac{1}{4}\)
X nhân 3\(\dfrac{2}{3}\)-1\(\dfrac{2}{3}\)=2\(\dfrac{1}{3}\)
\(\dfrac{3}{4}+\dfrac{1}{6}x3+\dfrac{2}{5}:\dfrac{4}{15}\)