ờm, cái kia hơi sai xíu
\(=\dfrac{5^{32}.\left[5.\left(2^2\right)\right]^{43}}{-\left(2^3\right)^{29}.\left(5^3\right)^{25}}=\dfrac{5^{32}.5^{43}.2^{86}}{-2^{87}.5^{75}}=\dfrac{5^{75}.2^{86}}{\left(-1\right).2^{87}.5^{75}}=\dfrac{1}{-2}\)
ờm, cái kia hơi sai xíu
\(=\dfrac{5^{32}.\left[5.\left(2^2\right)\right]^{43}}{-\left(2^3\right)^{29}.\left(5^3\right)^{25}}=\dfrac{5^{32}.5^{43}.2^{86}}{-2^{87}.5^{75}}=\dfrac{5^{75}.2^{86}}{\left(-1\right).2^{87}.5^{75}}=\dfrac{1}{-2}\)
5^32 × 20^43 / 8^29 × 125^25
5^32 × 20^43 / 8^29 × 125^25
RÚT GỌN : \(A=\frac{\left(-5\right)^{32}.20^{43}}{\left(-8\right)^{29}.125^{25}}\)
AI GIÚP MÌNH VỚI MAI MÌNH KIỂM TRA RỒI AI GIÚP MÌNH TICK CHO XIN CHÂN THÀNH CẢM ƠN !
(-5)32. 2043/ (-8)29.12525
(-5)32. 2043/ (-8)29.12525
(-5)32.2043/(-8)29.12525 = ?
Tính
(-5)32.2043/(-8)29.12525
Thực hiện phép tính:
Câu 1:
\(\frac{\left(-5\right)^{32}\cdot20^{43}}{\left(-8\right)^{29}\cdot125^{25}}\)
Câu 2:
\(\frac{5^4\cdot18^4}{125\cdot9^5\cdot16}\)
Câu 3:
\(\frac{9^{18}\cdot2^{29}}{8^9\cdot27^{12}}\)
(-5)32nhan 2043phan (-8)29nhan 12525
(-5)32*2043
(-8)29*12525