Điều kiện: \(x\ne0\)
\(-\dfrac{5}{12}:x=\dfrac{20}{-16}\\ \Rightarrow-\dfrac{5}{12}.\dfrac{1}{x}=-\dfrac{5}{4}\\ \Rightarrow-\dfrac{5}{12x}=-\dfrac{5}{4}\\ \Rightarrow12x=-5:-\dfrac{5}{4}=-5.-\dfrac{4}{5}=\dfrac{20}{5}=4\\ \Rightarrow x=\dfrac{4}{12}=\dfrac{1}{3}\left(thỏa.mãn\right)\)
Vậy x = \(\dfrac{1}{3}\)
\(\dfrac{3}{20}\)x\(\dfrac{7}{16}\)+\(\dfrac{3}{20}\)x\(\dfrac{5}{16}\)+\(\dfrac{3}{20}\)\(\dfrac{3}{10}\)
Tìm x, biết:
a) \(\dfrac{3}{4}x\) - \(\dfrac{7}{12}\) = \(\dfrac{5}{6}\) - \(\dfrac{2}{3}\)
b) -\(\dfrac{5}{x}\) = \(\dfrac{20}{28}\)
c) \(2\dfrac{1}{3}\) : x = 7
d) \(\dfrac{-105}{12}\) < x < \(\dfrac{20}{7}\)
1, A= \(\dfrac{-3}{4}.\left(0,125-1\dfrac{1}{2}\right):\dfrac{33}{16}-25\%\)
2, B= \(1\dfrac{13}{15}.0,75-\left(\dfrac{11}{20}+25\%\right):\dfrac{7}{3}\)
3, C= \(\dfrac{5}{16}:0,125-\left(2\dfrac{1}{4}-0,6\right).\dfrac{10}{11}\)
4, D= \(6\dfrac{5}{12}:2\dfrac{5}{4}+11\dfrac{1}{4}.\left(\dfrac{1}{3}-\dfrac{1}{5}\right)\)
7.Cho biết \(\dfrac{15}{x}=\dfrac{-3}{4}\) số x thích hợp là:
A. 20 B. -20 C. 63 D. 57
8.Tìm phân số tối giản trong các phân số sau:
A. \(\dfrac{6}{12}\) B. \(\dfrac{4}{16}\) C.\(\dfrac{-3}{4}\) D.\(\dfrac{15}{20}\)
\(\left(-3\right).\dfrac{-5}{9}\)
\(\dfrac{-12}{5}-x=\dfrac{-3}{5}\)
\(\dfrac{-20}{x}=\dfrac{-3}{5}\)
Ghi kq thoi cx dc 
\(\dfrac{12}{10} ; \dfrac{15}{25} ; \dfrac{16}{20} tăng dần\)
\(\dfrac{4}{3.5}\) + \(\dfrac{8}{5.9}\) + \(\dfrac{12}{9.15}\)+.......+
\(\dfrac{32}{x(x+16)}\) = \(\dfrac{16}{15}\)
\(\dfrac{32}{x(x+16)}\) = \(\dfrac{16}{15}\)
\(\dfrac{HeLp}{me}\) \(\dfrac{nguyễn}{đức}{Trí}\)
a) \(\dfrac{12}{16}\) = \(\dfrac{-x}{4}\) = \(\dfrac{21}{y}\) = \(\dfrac{z}{80}\)
b) \(\dfrac{1}{3}\) x + \(\dfrac{2}{5}\) ( x - 1 ) = 0
c) ( 2x - 3 )( 6 - 2x ) = 0
d) \(\dfrac{-2}{3}\) - \(\dfrac{1}{3}\) ( 2x - 5 ) = \(\dfrac{3}{2}\)
e) 2 |\(\dfrac{1}{2}\) x - \(\dfrac{1}{3}\) | - \(\dfrac{1}{4}\)
Bài3:Tìm x
a,\(\dfrac{x}{7}\)=\(\dfrac{6}{12}\) b,\(\dfrac{-5}{x}\)=\(\dfrac{20}{28}\) c,\(\dfrac{x-2}{8}\)=\(\dfrac{3}{4}\) d,\(\dfrac{x}{-5}\)=\(\dfrac{-5}{x}\)
các ban giúp mình nha, cảm ơn các bạn
