Ta có : \(\frac{4^{x+2}+4^{x+1}+4^x}{21}=\frac{3^{2x}+3^{2x+1}+3^{2x+3}}{31}\)
\(\Rightarrow\frac{4^x\left(4^2+4+1\right)}{21}=\frac{3^{2x}\left(1+3+3^3\right)}{31}\)
\(\Rightarrow\frac{4^x.21}{21}=\frac{3^{2x}.31}{31}\)
=> 4x = 32x
=> 4x = (32)x
=> 4x = 9x
=> \(\frac{4^x}{9^x}=1\)(vì lũy thừa của một số khác 0 luôn luôn là 1 số khác 0)
=> \(\left(\frac{4}{9}\right)^x=1\)
=> x = 0
Vậy x = 0
\(\frac{4^{x+2}+4^{x+1}+4^x}{21}=\frac{3^{2x}+3^{2x+1}+3^{2x+2}}{31}\)
a, 2x-3 / x+1 = 21/16
b, x-3 / x-5 = 6/7
c, 2x + 3 / 6 = 7x - 13 / 15
d, 2-x / 4 = 3x - 1 / -3
BT6:
A) (5x+1)^2=16/25
B) ( x - 1/3)^3=(2/3)^6
C)(8x - 1)^4=(2x+7)^4
D) (x -1)^5 =(2x-3)^5
E) ( x +1 )^8=(x+1)^10
G) (21-3)^4+(x+5)^6=0
H) 3x -4 = 81^3
help me
-4/7-x=3/5-2x
3/7.x-2/3.x=10/21
tìm x:
a) |4 - x| + 2x = 3
b) |x - 7| + 2x + 5 = 6
c) 3x - |2x + 1| = 2
d) |x + 2| - x = 2
e) |x - 3| = 21
f) |2x + 3| - |x - 3| = 0
g) |x + 1/8| + |x + 2/8| + |x + 5/8| = 4x
h) |x - 2| - |2x + 3| - x = -2
i) |2x - 3| - x = |2 - x|
k) 2. |x - 3| - |4x -1 = 0
Bài 1: Tìm x, biết
a) 3/7x - 2/3x =10/21
b) 7/35 : ( x- 1/3)=2/25
c) | 2x-4 |+1=5
d) 3.| 3 - 2x | - 1=2/5
e) 3.(x-1/2)-5(x+3/5)=-x+1/5
f) (2x-1).(x+2/3)=0
g) x+4/2008+x+3/2009=x+2/2010+x+1/2011
Thực hiện phép tính
a) (2x^4-5x^2+x^3-3-3x):(x^2-3) b) (x^5+x^3+x^2+1):(x^3+1)
c) (2x^3+5x^2-2x+3):(2x^2-x-1) d) (8x-8x^3-10x^2+3x^4-5):(3x^2-2x+1)
Mik cần gấppp
Tìm nghiệm : a) (2x-3).(2x+3) B)(x-4).(x-1).(x-2) C)2x(3x-1)-3x(5+2x) D)(3x-2).(3x+2)-4.(x-1)
Bài tập: Rút gọn biểu thức
A=|x-2| + |3-x| +|2x-5|+|10-2x|
B=3|x-3|+2|4-x|+|x|
C=-6|x+1|-3|2x+1|+5|x-1|
D=-|x|+|3x-1|-|4x+1|+|x-9|
E=5|x-7|-2|2x-7|+3|x+5|-4|4-2x|
