Question

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Answer 1

\(\left(1\right)FeCl_2+2NaOH\to Fe\left(OH\right)_2\downarrow +2NaCl\\ \left(2\right)Fe\left(OH\right)_2\xrightarrow{t^0}FeO+H_2O\\ \left(3\right)FeO+C\to Fe+CO\uparrow \\ \left(4\right)2Fe+3Cl_2\xrightarrow[]{t^o}2FeCl_3\\ \left(5\right)FeCl_3+3NaOH\to Fe\left(OH\right)_3\downarrow +3NaCl\\ \left(6\right)2Fe\left(OH\right)_3\xrightarrow{t^o}Fe_2O_3+3H_2O\\ \left(7\right)Fe_2O_3+3CO\xrightarrow{t^o}2Fe+3CO_2\\ \left(8\right)Fe+2HCl\to FeCl_2+H_2\)