Question

\(cot33^o+sin^225-tan57^o+sin^265^o-\dfrac{5tan24^o}{cot66^o}\)

\(\dfrac{sin27^o}{cos27^o}-7sin^265^o-7sin^225^o-tan27^o+tan45^o\)

\(sin^256^o-cot27^o+sin^234^o+tan63^o-12.tan37^o.tan53^o\)

Answer 1

\(cot33^0+sin^225^0-tan57^0+sin^265^0-5\cdot\dfrac{tan24^0}{cot66^0}\)

\(=tan57^0-tan57^0+sin^225^0+cos^225^0-5\)

=0+1-5=-4

\(\dfrac{sin27^0}{cos27^0}-7\cdot sin^265^0-7\cdot sin^225^0-tan27^0+tan45^0\)

\(=tan27^0-7\left(sin^265^0+cos^265^0\right)-tan27^0+1\)

=-7+1=-6

\(sin^256^0-cot27^0+sin^234^0+tan63^0-12\cdot tan37^0\cdot tan53^0\)

\(=\left(sin^256^0+cos^256^0\right)-cot27^0+cot27^0-12\)

=1-12=-11